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Q: How do you make 10 triangles out of 5 lines?
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How do you make 5 triangles on a pentagon with 2 lines?

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Simple: Draw a star! It took my friend 3 YEARS TO FIGURE IT OUT :0


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I get 9 triangle with fewer than 9 lines. Draw a square: ABCD (4 lines) Draw the diagonals AC, BD (2 lines) which meet at X in the centre. On a separate part of the page, draw triangle PQR (3 lines). That is 4 + 2 + 3 = 9 lines. The triangles are: ABC, BCD, CDA, DAB, AXB, BXC, CXD, DXA, and PQR 9 triangles with 9 lines. Could have done 13 triangles with 7 lines by drawing a line from A to BC.


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Are all right-angled triangles congruent?

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