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(3-1) x (2+8)(9-6)

Essentially, the above sum is 2x103

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12y ago
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1y ago

One possible way to make 2000 using numbers between 1 and 9 once is: 9^3 − 8 × 7 − 6 × 5 × 4 − 3 × 2.

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Q: How do you make 2000 using numbers between 1 and 9 once?
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