5! / 4 - 2 * 3
106------------------------------------------------------------------------------------------------From Rafaelrz.You can make, 4P3 = 4!/(4-3)! = 24, different 3 digit numbers using 1, 2, 3 and 4.
24
7-3= 4-1= 3x8= 24
To get 24 using 1 3 4 and 6 once you do 6 times 4
8*3*(4-3) = 24
6/(1-3/4)=24
First way: (3/3 + 5) * 4 = 24 Second way: (5-3) * (4*3) = 24
5+3=8 8-4=4 4*6=24
5 * 5 + 3 - 4 is one way.
5! / 4 - 2 * 3
106------------------------------------------------------------------------------------------------From Rafaelrz.You can make, 4P3 = 4!/(4-3)! = 24, different 3 digit numbers using 1, 2, 3 and 4.
24
One possible solution: (3 + 3)*(1*3/3 + 3) = 6 * 4 = 24
Multiply 6 and 4. Multiply 8 and 3.
Well, isn't that a happy little problem to solve! Let's see, you can add 9 and 6 to get 15, then multiply that by 2 to get 30. Finally, subtract 4 to get 24. Just like that, you've created a beautiful equation!
24