No, use 25 4s.
It rather depends on how many 4s there are in the stack. It's (however many 4s there are) to 25. If you had a standard pack of playing cards then there are 52 cards of which four are 4s, so your odds are 4 in 52, or 1 in 13.
The answer is 4! - [(4+4)/4]
(4x4)-(4/4) = 15
4! - sqrt 4 + 4/4
4+4+4x4 by the power of 0.
if you want to make eleven using only four 4s, this is the answer 4/.4+4/4(=10 + 1= 11) TA DA !
(4+4)*(4+4)=8*8=64
4/.4 + 4/4 [= 10+1 = 11]
(44 - 4)/4
44/4 + 4! = 11 + (4x3x2x1) = 11 + 24 = 35
4! - sqrt(4)*sqrt(4)/4 = 23