0
Want this question answered?
Be notified when an answer is posted
Add your answer:
Earn +20 pts
What is 1m x 1m x 0.5m?
1m*1m*0.5m=0.5m3
How many millmeters make 1 square meter?
"Millimeter" is a unit of length, and "square meter" is a unit of area. So you can't compare.If by chance you meant "How many square millimeters make 1 square meter?" then here it is.1 m2 is an area of a 1m * 1m square.1m * 1m = 1000mm * 1000mm1000mm * 1000mm = 1,000,000mm2.Hope it helped :)
How many square mm make 1 meter?
50 square mm because 12mm 12 meter 1mm 1m 100mm= 1m
How many millmeter make 1 meter?
1000 mm = 1m
What fraction of 1m of 77cm?
1m = 100 cmAnswer:77/100 of 1m
How do you prepare 1M from 10mM Tris-HCL?
To prepare 1M Tris-HCl from a 10mM solution, you would need to dilute the 10mM solution by a factor of 100. This means you would mix 1 part of the 10mM solution with 99 parts of water to achieve a final concentration of 1M Tris-HCl.
How do you prepare 10mM Tris?
To prepare 10mM Tris solution, first calculate the amount of Tris base needed based on the molecular weight of Tris (121.14 g/mol). Weigh out the appropriate amount of Tris base and dissolve it in water to make a final volume of 1L. Adjust the pH to the desired value if necessary.
How do you make 1X TE buffer?
10 mM Tris pH 7.5 and 1mM EDTA pH 8.0 For 1 L : 10 mL of 1M Tris-Cl pH 7.5 and 2 mL of 500mM EDTA pH 8.0
What Volume of 5M HCl to make tris buffer at pH 7.5?
To make a Tris buffer at pH 7.5, you will need to mix Tris base with HCl. To calculate the volume of 5M HCl needed, you will first need to determine the molarity of the Tris buffer solution and then use the Henderson-Hasselbalch equation. The exact volume of 5M HCl required will depend on the amount of Tris base used and the final volume of the buffer solution.
How do you prepare 0.1M tris HCl buffer of pH 8?
Tris(hydroxymethyl)aminomethane (Tris) has a molecular weight of 121.14 g/mol. 50 mM = 0.050 mol/L (x 121.14 g/mol) = 6.057 g/L To prepare a 1L solution first weigh out 6.057 g Tris Add roughly 70% of final volume of water (i.e. 700 mL) Use a pH-meter to measure the pH of the solution Lower the pH of the solution to 7.2 using undiluted HCl Use a measuring cylinder or volumetric flask to make the volume up to 1000 mL If you add too much HCl you need to add more Tris and then recalculate the amount of water that you need add. In this case, every 1 g of Tris requires 165 mL of water to be added.
How do you make 62.5 mM Tris-HCl?
To make 62.5 mM Tris-HCl solution, you would need to mix the appropriate amount of Tris base and HCl to achieve a final concentration of 62.5 mM. The calculation involves considering the molecular weights of Tris and HCl to determine the amount needed to make the desired concentration.
How do you prepare 10mM solution of Tris-HCl?
To prepare a 10mM solution of Tris-HCl, you would weigh out the appropriate amount of Tris-HCl powder using a balance and dissolve it in water to make a final volume of solution. For example, to make 1L of 10mM Tris-HCl solution, you would need to dissolve 0.121g of Tris-HCl in 1L of water.
What is the difference between tris tris cl and tris hcl?
Tris(hydroxymethyl)aminomethane (Tris) is a common buffer used in biochemistry, while Tris HCl is Tris buffer combined with hydrochloric acid to adjust the pH. Tris buffer is neutral (pH 7-9), while Tris HCl is acidic with a pH around 4.5-8.6.
How do you make a 1 mol tris buffer?
To make a 1 mol tris buffer, you would need to dissolve 121.1 g of Tris (Tris(hydroxymethyl)aminomethane) in water and dilute to a final volume of 1 liter. Adjust the pH with a strong acid like HCl or a strong base like NaOH to reach the desired pH of the buffer.
How do you make 2M HCL in 100ml from 36 percent Hcl?
To prepare 2M HCl in 100ml from 36% HCl: Calculate the volume of 36% HCl that you need to obtain the desired concentration by using the formula C1V1 = C2V2. Dilute the calculated volume of 36% HCl with water to reach a final volume of 100ml while maintaining the molarity.
How many ml must be added to 270 ml to make halve a liter?
1L = 1000mL 1/2L = 500mL 500mL - 270mL = 230mL
If you have 2 liters of 2 M NaCl you take 500 ml of that and add it to 500ml of pure water the new 1000 ml preparation is now?
A solution of NaCl 1 M.
