Assuming this is mathematical style question from the first ever programme broadcast on Channel 4 where all 6 numbers do not have to be used:
(100 + 9 + 2) x (3 + 4) = 111 x 7 = 777
To find the average of 575 and 777, you add the two numbers together and then divide by 2. So, ( (575 + 777) / 2 = 1352 / 2 = 676 ). Therefore, the average of 575 and 777 is 676.
2 prime numbers which make 100: 3 + 97; 11 + 89; 17 + 83; 29 + 71; 41 + 59
79 + 19 + 2
The prime numbers of 100 are: 2, 2, 5 and 5
To find how many numbers between 1 and 100 inclusive are divisible by 2, we can identify the even numbers in that range. The even numbers from 1 to 100 are 2, 4, 6, ..., 100. This forms an arithmetic sequence where the first term is 2, the last term is 100, and the common difference is 2. There are 50 even numbers (2, 4, 6, ..., 100), so there are 50 numbers between 1 and 100 that are divisible by 2.
To find the average of 575 and 777, you add the two numbers together and then divide by 2. So, ( (575 + 777) / 2 = 1352 / 2 = 676 ). Therefore, the average of 575 and 777 is 676.
2 prime numbers which make 100: 3 + 97; 11 + 89; 17 + 83; 29 + 71; 41 + 59
2 x 2 x 5 x 5 = 100
47 + 53
97 & 3
As a product of its prime factors: 2*2*5*5 = 100
As a product of its prime factors: 2*2*5*5 = 100
As a product of its prime factors: 2 * 2 * 5 * 5 = 100
79 + 19 + 2
In Java:System.out.println("Even numbers")for (int i = 2; i
All of the numbers from 1 to 100 are the factors in the set of numbers from 2 to 100.
24*6= 16 777 216 8 * 2 097 152 = 16 777 216