140 70,2 35,2,2 7,5,2,2
The factor tree is as follows: 114 57,2 19,3,2
Since 61 is already prime, a factor tree is not necessary. The prime factorization of 51 is 3 x 17, which wouldn't make much of a tree. More like a factor shrub.
119 7,17
question:make a factor tree for 36. 6 to the fifth power 6to the fifther power time 6
140 70,2 35,2,2 7,5,2,2
140 70,2 35,2,2 7,5,2,2
70,2 35,2,2 7,5,2,2
98 49,2 7,7,2 140 70,2 35,2,2 7,5,2,2
Use a factor tree. 98 49.2 7,7,2 140 70,2 35,2,2 7,5,2,2
140 2, 70 2, 2, 35 2, 2, 5, 7
140 70,2 35,2,2 7,5,2,2 2 x 2 x 5 x 7
The factor tree is as follows: 114 57,2 19,3,2
no
Oh, dude, making a factor tree for 7 is like, super easy. You just start with 7 at the top, and then realize that 7 is a prime number, so it only has 1 and 7 as factors. So, your factor tree is basically just a stick with 7 at the top. Voilà!
No.
yes