Any number, A, raised to some power, x, can be written in the form, A^x in keyboard form.E.g. five squared would be written 5^2.
3 x 10-5 10 raised to -5 is 0.00001. Multiply by 3 to get answer.
3.33... (recurring) cubic yards.
(x5+ 5) / (x+5) = x^4 - 5x^3 + 25 x^2 - 125 x + 625 + (-3025 +5)/(x+5) = x^4 - 5x^3 + 25 x^2 - 125 x + 625 - 3020/(x+5) If I understand the problem correctly, that can't be simplified. You can only get an actual value if you substitute a value for "x".
5 x 5 x 5 x 11
55 = 3125 5 x 5 x 5 x 5 x 5 = 3125 The answer can be obtained via a calculator or by the use of logarithms.
The prime factorization of 630 is 2 x 3^2 x 5 x 7. This means that 630 can be expressed as the product of these prime numbers raised to their respective exponents. In this case, we have 2 raised to the power of 1, 3 raised to the power of 2, 5 raised to the power of 1, and 7 raised to the power of 1.
9.313226 x 1020 (rounded)
0
5 raised to the power 3 equals 5 x 5 x 5 = 125 a to the power of 3 equals a x a x a zero to the power 3 = 0 x 0 x 0 = 0 zero to the power 10 = 0 x 0 x 0 x 0 x 0 x 0 x 0 x 0 x 0 x 0 = 0 So you can see that no matter how many times we multiply zero by itself the answer is always zero. Hence zero raised to the power zero equals zero
mass of proton is 6 x pi raised to power 5 times mass of electron
Any number raised to the power 1 is that same number, x1 = x. For example, 51 = 5.
Any number, A, raised to some power, x, can be written in the form, A^x in keyboard form.E.g. five squared would be written 5^2.
3 x 10-5 10 raised to -5 is 0.00001. Multiply by 3 to get answer.
9 x 105 = 900,000
Short for a perfect cube - an integer raised to the third power. For example, 125, which is the cube of 5 (53 = 5 x 5 x 5 = 125).
3.33... (recurring) cubic yards.