Q: How do you prepare 0.002 N Na2S2O3?

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To prepare a 0.1N Na2S2O3 solution, dissolve 24.98 grams of Na2S2O3·5H2O (sodium thiosulfate pentahydrate) in distilled water and dilute to 1 liter in a volumetric flask. This will give you a 0.1N (normal) solution of Na2S2O3.

To prepare 0.2M solution of anhydrous sodium thiosulfate (Na2S2O3), you dissolve 24.6g of anhydrous Na2S2O3 in distilled water and dilute it to 1 liter. This is the molar mass method, where molar mass of Na2S2O3 is 158.10 g/mol.

first we calculate the molecular weight M.W=158.11 mass of Na2S2O3=M.W*concentration*volume(in litter) for a concentration of 0.001 mass of Na2S2O3=158.11*0.001*1=0.15811 g so we use this mass and continue the volume to be 1 L

To prepare a 0.1N solution of sodium thiosulfate, we need to weigh out 25 grams because each mole of sodium thiosulfate (Na2S2O3) is equivalent to 248.18 grams. Given that the formula weight is known, 25 grams gives the correct molarity of the solution.

To calculate the mass needed, you first need to determine the molar mass of Na2S2O3•5H2O. Then use the formula: mass = molarity (M) x volume (L) x molar mass (g/mol). Substitute the values to find the mass of Na2S2O3•5H2O needed.

1167

Na2S2O3(aq) + 2HCL(aq) => 2NaCl(aq) + S(s) + SO2(g) + H2O(l)

a number

To prepare 0.02M sodium thiosulfate solution, weigh out the required amount of sodium thiosulfate pentahydrate (Na2S2O3·5H2O) or anhydrous sodium thiosulfate (Na2S2O3). Dissolve this in distilled water and make up the volume to the desired concentration. Make sure to use a volumetric flask for accuracy and precision in preparing the solution.

0.003 is bigger, but not by much.

Na2S2O3

Sodium thiosulfate