1/101 is then added, the result is 10001/999900
Yes 10001 equals 17 in binary. 0=0 1=1 10=2 11=3 100=4 101=5 110=6 111=7 1000=8 10000=16 and so on... In your example 10001 = 16 plus 1 which is 17.
Doen't anybody care that the binary numbers at the head of the page is incorrect? There is no 11, although the answer below is correct. 1 10 11 100 101 110 111 1000 1001 1010 1011 1100 1101 1110 1111 10000 10001 10010 10011 10100
1/99 − 1/100 = 1/9900, and if 1/101 is then added, the result is 10001/999900
1/101 is then added
10^n+1
1, 2, 5, 10, 101, 202, 505, 1010.
The positive integer factors of 1010 are: 1, 2, 5, 10, 101, 202, 505, 1010
1/101 is then added, the result is 10001/999900
1 times 101 or 0.1 times 1010 are two examples.
for (int row=0; row<4; ++row) { int i = 1; for (int col=0; col<=row; ++col) { printf ("%d", i); i=(i==1?0:1); } }
1 10 11 100 101 110 111 1000 1001 1010 1011 1100 ...1 10 11 100 101 110 111 1000 1001 1010 1011 1100 ...1 10 11 100 101 110 111 1000 1001 1010 1011 1100 ...1 10 11 100 101 110 111 1000 1001 1010 1011 1100 ...
Yes 10001 equals 17 in binary. 0=0 1=1 10=2 11=3 100=4 101=5 110=6 111=7 1000=8 10000=16 and so on... In your example 10001 = 16 plus 1 which is 17.
Doen't anybody care that the binary numbers at the head of the page is incorrect? There is no 11, although the answer below is correct. 1 10 11 100 101 110 111 1000 1001 1010 1011 1100 1101 1110 1111 10000 10001 10010 10011 10100
1/99 − 1/100 = 1/9900, and if 1/101 is then added, the result is 10001/999900
1/101 is then added
1/101 is then added