The simplest way is to divide 748 by 4 and show that there is no remainder. That proves it.
A longer, but more general proof is as follows:
25*4 = 100 so 100 is dividsible by 4.
By the distributive property, you can show that any number of hundreds (eg 700) is divisible by 4.
So, to prove that 748 is divisible by 4, it is only necessary to show that the number formed by the last two digits (48) is divisible by 4.
This is easy, since 12*4 = 48.
The second method is not much of an advantage with a number like 748, but it would be if you were asked to prove that 75612349248 was divisible by 4!
748/16 = 187/4 = 46 3/4 or as a decimal: 46.75
A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.
69% of 748= 69% * 748= 0.69 * 748= 516.12
Yes 1124 is divisible by 4. Since 24 is divisible by 4 1124 is divisible by 4. If the last two numbers of a number are divisible by 4, the number is divisible by 4. 24 divided by 4 is 6.
no it is not divisible by 4
No it isn't
4
No because the digital sum of 748 does not finally add up to 9
187
748/16 = 187/4 = 46 3/4 or as a decimal: 46.75
187 is divisible by 17 and 11. 187 divided by 17=11.
The factors of 748 are: 1, 2, 4, 11, 17, 22, 34, 44, 68, 187, 374, and 748.The prime factors of 748 are: 2, 11, and 17.
748 = (7 x 100) + (4 x 10) + (8 x 1)
A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.
4 is not divisible by 684. 684 is divisible by 4.
Becuz 8 mutiplied by 3 is 24
69% of 748= 69% * 748= 0.69 * 748= 516.12