The idea is to get rid of the square root in the denominator. For this purpose, you must multiply numerator and denominator by the square root of 6 in this case.
It looks like your question is [1-sqrt(3)] / [1+sqrt(3)], and you want to rationalize the denominator. If this is the case, multiply both numerator and denominator by (1-sqrt(3)), and get for the denominator = -2, and the numerator = 4 - 2*sqrt(3), so the answer is sqrt(3) - 2
You can rationalize the denominator by multiplying this fraction by a fractional form of one in radical form. 3/sqrt(2) * sqrt(2)/sqrt(2) = 3sqrt(2)/2 ----------------
If you are referring to 1/sqrt7 then you multiply the numerator and denominator by sqrt7 over sqrt7. 1 = (1)sqrt7 = sqrt7 sqrt7 (sqrt7)sqrt(7) 7
its false apex :)
The idea is to get rid of the square root in the denominator. For this purpose, you must multiply numerator and denominator by the square root of 6 in this case.
If you want to rationalize the denominator, then multiply numerator & denominator by sqrt(5), so 8*sqrt(5)/5 = approx 3.578
It is √3/3 or "root three over three."√1/√3 ("the square root of one-third")1/√3 ("one over root three") (The square root of one is one.)√3/3 ("root three over three") (Rationalize the denominator.)
It looks like your question is [1-sqrt(3)] / [1+sqrt(3)], and you want to rationalize the denominator. If this is the case, multiply both numerator and denominator by (1-sqrt(3)), and get for the denominator = -2, and the numerator = 4 - 2*sqrt(3), so the answer is sqrt(3) - 2
You can rationalize the denominator by multiplying this fraction by a fractional form of one in radical form. 3/sqrt(2) * sqrt(2)/sqrt(2) = 3sqrt(2)/2 ----------------
If you are referring to 1/sqrt7 then you multiply the numerator and denominator by sqrt7 over sqrt7. 1 = (1)sqrt7 = sqrt7 sqrt7 (sqrt7)sqrt(7) 7
its false apex :)
3.5714
The square root needs to be removed from the bottom. To do this multiply the numberater and denominator by the square root of 5. 125xsquare root of five over 5 25square root of 5 is the simplest answer.
Yes. The square root of a fraction is the square root of the numerator over the square root of the denominator. First simplify the fraction (making mixed numbers into improper fractions). Now consider the numerator and denominator separately as whole numbers. Only perfect squares (the squares of whole numbers) have rational square roots. If either, or both, of the numerator and denominator is not a perfect square, the square root of the fraction will be irrational √(11/6) = (√11)/(√6). Neither 11 nor 6 is a perfect square, thus √(11/6) is irrational.
The concept of common denominator makes sense to numbers whose denominators are integers. If the context of fractions, any denominator is divisible by any other [non-zero] number.
Well, honey, to find the square root of 625 over 36, you first find the square root of the numerator (625) which is 25, and the square root of the denominator (36) which is 6. So, the square root of 625 over 36 is 25 over 6. Math doesn't have to be as complicated as your ex's drama, darling.