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Generally, the process involves multiplying the numerator and denominator of the fraction by the same number. This number is selected so that the original denominator becomes rational. In the process the numerator may become rational.
If the original denominator is of the form √b then you multiply the numerator and denominator by √b/√b.
If the original denominator is of the form a+√b then you multiply the numerator and denominator by (a-√b)/(a-√b). NOTE change of sign.
There is a similar process, using complex conjugates, if the denominator is a complex number.
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When dividing complex numbers the first step is to multiply the top and bottom by the complex ----- of the denominator?
"conjugate" That step is called "rationalizing the denominator", although it actually makes the denominator 'real', but not necessarily 'rational'.
How do you convert the complex number to standard form 1 plus 2i over root2 plus i?
Multiply the numerator and denominator by the complex conjugate of the denominator ... [ root(2) minus i ]. This process is called 'rationalizing the denominator'.
A method used to eliminate radicals from the denominator of a fraction?
That is called "rationalizing the denominator". It consists of multiplying the numerator and the denominator by specific terms, which include square roots. Examples:* If the denominator is root(2) (that is, the square root of 2), multiply numerator and denominator by root(2). * If the denominator is root(2) + root(3), multiply numerator and denominator by root(2) - root(3).
Which operation involves complex numbers requires the use of a conjugate to be carried out?
One operation that is used a lot in quantum mechanics is taking the absolute value of the square of a complex number. This is equivalent to multiplying the complex number by its complex conjugate - and doing this is simpler in practice.
Find the square root of the square root of one fourth.?
The square root of the square root is basically the exponent of 1/4- thus, sqrt(sqrt(1/4)) = 11/4/41/4 = 1/sqrt(2).Rationalizing the denominator yields sqrt(2)/2.
