2 goes into 7 3 times with one left over so you put 3 and 1 over 2
2/7
it can't reduce any smaller so 2 over 15 is your answer
14/35 is 2/5 in its reduced terms
No; 7 / 20 is irreducible.
No, because if you reduce 12/36 then you get 3 and if you reduce 5/7 you get a decimal, not 3.
2/7
It reduces to 2/7
No, but 15/2 can be changed to mixed number, 7 1/2.
it can't reduce any smaller so 2 over 15 is your answer
YES!!!! 14/35 '7' is a factor in both numbers. 7 X 2 = 14 7 x 5 = 35 So cancel down /reduce by '7' Hence 14/35 = 2/5 NB Facility with your 'ten times tables' ( Multiplication) will speed/quicken the working of these type of problems.
There is no way to reduce 7 over 8 because it is already in simplest form.
d.
No
14/35 is 2/5 in its reduced terms
No; 7 / 20 is irreducible.
It is: 7/8 plus 5/8 = 12/8 or 3/2 in its lowest terms
4/7