To restore a Sears Mod 273.2341 sewing machine, start by cleaning it thoroughly, removing dust and debris from the exterior and interior mechanisms. Next, oil all moving parts according to the manufacturer's specifications, using the appropriate sewing machine oil. Replace any worn or damaged parts, such as belts or needles, and ensure that the machine is properly threaded and adjusted for tension. Finally, test the machine on fabric to ensure it stitches smoothly and make any necessary adjustments.
36288 WRONG!(1*2*3*4*5*6*7*8*9)/10 WRONG!I obviously misreads the question. after writing a simple visual basic program, see below. I am changing my answer to "does not exist." as the program failed to return a value.Private Sub Command0_Click()Dim i As Longi = 1Do While i Mod 9 > 0 Or i Mod 10 = 0i = i + 1Do While i Mod 8 > 0 Or i Mod 10 = 0i = i + 1Do While i Mod 7 > 0 Or i Mod 10 = 0i = i + 1Do While i Mod 6 > 0 Or i Mod 10 = 0i = i + 1Do While i Mod 5 > 0 Or i Mod 10 = 0i = i + 1Do While i Mod 4 > 0 Or i Mod 10 = 0i = i + 1Do While i Mod 3 > 0 Or i Mod 10 = 0i = i + 1Do While i Mod 2 > 0 Or i Mod 10 = 0i = i + 1LoopLoopLoopLoopLoopLoopLoopLoopMsgBox iEnd Sub
9100 mod 10 = (910 mod 10)10 mod 10 = 110 mod 10 = 1. Thus 1 is the ones digit in 9100.
Sears, founded in 1892, would be 131 years old in 2023. The number 126.7966020 appears to be a decimal and does not relate to Sears' age directly. If you meant to inquire about something else related to Sears or that number, please clarify!
Numbers. i^n = i^(n mod 4). With n = 27, 27 mod 4...
A number is divisible by 6 if it is divisible by 2 and 3. Look at 333-3 which is 330 The sum of the digits is 6 and it is even so it is divisible by 6 Now consider 222-2 which I picked because unlike 333, 222 has even digits. 222-2=220, one again even number so divisible by 2 but NOT divisible by 3 so NOT divisible by 6 So it look like this is not true for all n For any odd n, we have the following 1. nnn-n ends in 0 so it is even if we can show it is divisible by 3 we are done. but 777-7 is 770 which is NOT divisible by 3 so it is NOT true. For some n it is true, but not for all n... Now when will nnn-n be divisible by 3. only when n+n is a multiple of 3, ie n=33,66, 99 an that is it! So we could easily prove that nnn-n is divisible by 6 if and only if n=3,6,or 9 ----------------------------- If by nnn, you mean n3, a proof is as follows: n=0,1,2,3,4, or 5 (mod 6) If n=0 (mod 6), we have (0 (mod 6))((0(mod 6))2-1)=0 (mod 6). [Since the first term is zero] If n=1 (mod 6), we have (1 (mod 6))((1(mod 6))2-1)=0 (mod 6) [Since 1-1=0]. If n=2 (mod 6), we have (2 (mod 6))((2(mod 6))2-1)=(2*3) (mod 6) = 6 (mod 6)=0 (mod 6). If n=3 (mod 6), we have (3 (mod 6))((3(mod 6))2-1)=(3*8) (mod 6) = 24 (mod 6) = 0 (mod 6). If n=4 (mod 6), we have (4 (mod 6))((4(mod 6))2-1)=(4*15) (mod 6) = 60 (mod 6) = 0 (mod 6). If n=5 (mod 6), we have (5 (mod 6))((5(mod 6))2-1)=(5*24) (mod 6) = 120 (mod 6) = 0 (mod 6). If you're not comfortable with the modular arethmetic, you can substitue 6m+_, where the blank is each of the numbers 0 through 5 (since every number can be expressed either as a multiple of six, or as a multiple of six plus some number between 1 and 5 --the remainder when the number is divided by six). Taking our example with 5, you would get: (n)(n2-1) can be written as (6m+5)((6m+5)2-1), where m is an integer. Simplifying this, you get: (6m+5)((6m+5)2-1) (6m+5)((6m2+60m+25-1) 6m*6m2+6m*60m+6m*25-6m+5*6m2+5*60m+5*25+5(-1) 6m*6m2+6m*60m+6m*25-6m+5*6m2+5*60m+5*24 Since m is an integer and each term is divisible by 6, (n)(n2-1) is divisible by 6 for integers that can be expressed as 6m+5. You would then repeat the process for each of 0 through 4 to complete the proof. Clearly, if you are comfortable with it, modular arithmetic is the less cumbersome way to proceed.
go to sears pick up a magazine and wow u have a sears magazine
The Sears Model 1 may be a Winchester mod 121. L0ok there
The Sears mod. 66 was made by High Standard for Sears and is a High Standard mod. 66. If you have anymore questions please do not hesitate to email me at eagle44mag@adelphia.net. Thanks, Rick
That would cross to a poulan 2800. Scott www.chainsawr.com
sears 22mag mod no273,2350
A Sears Mod 53 is a Winchester Mod 70. If Sears doesn't have an owner's manual for the 53 (and you can't find one on eBay), go here http://www.stevespages.com/page7b.htm for a Winchester manual.
Where can you locate a parts breakdown and availability for a Sears mod. 42-103-2840-22 caliber rifle?
What is the value of a Sears Roebuck 22SL OR LR MOD #27327010
Winchester 70
Try e-gunparts.com
Need model number
I have a sears and robuck 20 ga. pump with adjustable choke on the end of the barrel