Q: How do you show the number 75 as a product of prime numbers?

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2 x 2 x 3 x 7 = 84

All composite numbers can be expressed as unique products of prime numbers. This is accomplished by dividing the original number and its factors by prime numbers until all the factors are prime. A factor tree can help you visualize this. Example: 210 210 Divide by two. 105,2 Divide by three. 35,3,2 Divide by five. 7,5,3,2 Stop. All the factors are prime. 2 x 3 x 5 x 7 = 210 That's the prime factorization of 210.

It will take six. 2 x 2 x 2 x 2 x 2 x 2 = 64

Both of these are acceptable for 640:2 x 2 x 2 x 2 x 2 x 2 x 2 x 5 = 64027 x 5 = 640

That's an infinite list.

Related questions

Showing a composite number as a product of prime numbers is called prime factorization.

24 as a product of prime numbers is 2 x 2 x 2 x 3.

Impossible. The number is infinite.

There are no prime numbers in that range.

2 x 2 x 3 x 7 = 84

All composite numbers can be expressed as unique products of prime numbers. This is accomplished by dividing the original number and its factors by prime numbers until all the factors are prime. A factor tree can help you visualize this. Example: 210 210 Divide by two. 105,2 Divide by three. 35,3,2 Divide by five. 7,5,3,2 Stop. All the factors are prime. 2 x 3 x 5 x 7 = 210 That's the prime factorization of 210.

23 is a prime number so there is no prime factorization. Some consider it to be acceptable to write 1 X 23 in order to show the number is prime, even though 1 is not a prime or composite number.23 is already prime.

The surviving records of the ancient Egyptians show that they had some knowledge of prime numbers

A prime number can only be multiplied by one or by itself.the best part about this is that the only even prime number is two...others are all odd numbers. What im trying to do is not just giving you the answer...but if I show you how to do it you could turn it into a two minute problem :D

No. The easiest counter-example to show that the product of two irrational numbers can be a rational number is that the product of √2 and √2 is 2. Likewise, the cube root of 2 is also an irrational number, but the product of 3√2, 3√2 and 3√2 is 2.

Both of these are acceptable for 640:2 x 2 x 2 x 2 x 2 x 2 x 2 x 5 = 64027 x 5 = 640

We know that a prime number is a positive integer greater than 1, whose divisors are 1 and itself. We know that the only even prime number is 2. That means that all other prime numbers are odd numbers.We know that when we add two odd numbers the result is an even number, which are not prime numbers (expect 2, and 2 = 1 + 1 where 1 is odd but is neither prime nor composite). Thus adding two odd prime numbers cannot give us another prime number. We show that the conclusion follows from the premise:Assume that r = p + q where all r, p and q are prime numbers, then we have that ris either even or not:* If r is even then r is at least 4 (the smallest number which is the sum of two primes) and thus not a prime number. This contradicts the assumption that r is a prime number, and therefore we conclude that r is not even. * If ris odd then either p or q must be odd and the other one must be even, since both p and q are prime numbers one of them must be 2 (the only even prime number). 2 + 3 = 5, 2 + 17 = 19, are examples of such numbers. See http://en.wikipedia.org/wiki/Twin_prime for more.