To simplify the expression (10n - 4n), you combine the like terms. Subtract (4n) from (10n) to get (6n). Therefore, the simplified expression is (6n).
20n2+6n-2 (4n + 2)(5n -1) This problem can be solved by FOILing. First, multiply the first terms to get 20n2 Next, multiply the outside terms to get -4n. Multiplication of the inside terms results in 10n. Combining -4n and 10n (they are like terms) is 6n. Then, multiply the last terms, to get -2. Combining these answers into one equation gives the answer of 20n2+6n-2.
An=A¹+(n-1)d 300=200+(n-1)4 300-200=4n-4 100+4=4n ¼(104=4n) 26=n An=A¹+(n-1)d 300=200+(n-1)10 300-200=10n-10 100+10=10n ⅒(110=10n) 11=n Find the least common multiple of (4,10) 4 8 12 20 24 10 20 30 LCM=20 Then we are going to find the numbers between 200 and 300 that are divisible by 20. 200, 220, 240, 260, 280, 300 We have 6 numbers 26+11=37-6= 31 The answer is 31
10n is basically 10 times something. Example: 10n = 100/n=10
To simplify the expression (7n - 2) + (3n + 4), first, combine like terms. This gives you 7n + 3n - 2 + 4, which simplifies to 10n + 2. Thus, the simplified form of the expression is 10n + 2.
Start by factoring each part. If you find a common factor in the numerator and the denominator, eliminate it in both.
The net force is the difference between the 10N falling object and the 4N of air resistance So you solve 10N-4N is 6N
10n+12 = 14n-12 10n-14 = -12-12 -4n = -24 n = 6
4n
20n2+6n-2 (4n + 2)(5n -1) This problem can be solved by FOILing. First, multiply the first terms to get 20n2 Next, multiply the outside terms to get -4n. Multiplication of the inside terms results in 10n. Combining -4n and 10n (they are like terms) is 6n. Then, multiply the last terms, to get -2. Combining these answers into one equation gives the answer of 20n2+6n-2.
8m + (4n - 6m) + 9n =8m + 4n - 6m + 9n =(8m - 6m) + (4n + 9n) =2m + 13n
The total force you would get by adding a 6N force with a 4N force is 10N. This is because forces can be added together like numbers in mathematics to get the total force applied.
An=A¹+(n-1)d 300=200+(n-1)4 300-200=4n-4 100+4=4n ¼(104=4n) 26=n An=A¹+(n-1)d 300=200+(n-1)10 300-200=10n-10 100+10=10n ⅒(110=10n) 11=n Find the least common multiple of (4,10) 4 8 12 20 24 10 20 30 LCM=20 Then we are going to find the numbers between 200 and 300 that are divisible by 20. 200, 220, 240, 260, 280, 300 We have 6 numbers 26+11=37-6= 31 The answer is 31
n - 10 + 9n - 3 n + 9n - 10 - 3 10n - 13
q = quarters etc. 2q or 1q+2d+1n or 1q+1d+3n or 5d or 4d+2n or 3d+4n or 2d+6n or 1d+8n or 10n
10n=40
what is 10n=40
4n is multiplied by 4n.