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What is 4n plus 2 times 5n minus one?
20n2+6n-2 (4n + 2)(5n -1) This problem can be solved by FOILing. First, multiply the first terms to get 20n2 Next, multiply the outside terms to get -4n. Multiplication of the inside terms results in 10n. Combining -4n and 10n (they are like terms) is 6n. Then, multiply the last terms, to get -2. Combining these answers into one equation gives the answer of 20n2+6n-2.
How many integers between 197 and 303 divisible by 4?
An=A¹+(n-1)d 300=200+(n-1)4 300-200=4n-4 100+4=4n ¼(104=4n) 26=n An=A¹+(n-1)d 300=200+(n-1)10 300-200=10n-10 100+10=10n ⅒(110=10n) 11=n Find the least common multiple of (4,10) 4 8 12 20 24 10 20 30 LCM=20 Then we are going to find the numbers between 200 and 300 that are divisible by 20. 200, 220, 240, 260, 280, 300 We have 6 numbers 26+11=37-6= 31 The answer is 31
How do you simplify the rational expression 4n-4 divided by 6n-20?
Start by factoring each part. If you find a common factor in the numerator and the denominator, eliminate it in both.
What does 10N mean?
10n is basically 10 times something. Example: 10n = 100/n=10
What it 4n - 14 equals 22?
4n -14 = 22 4n = 22+14 4n = 36 n = 9
What is the net force that acts on a 10N falling object when it encounters 4N of air resistance?
The net force is the difference between the 10N falling object and the 4N of air resistance So you solve 10N-4N is 6N
How do you solve 10n plus 12 equals 14n-12?
10n+12 = 14n-12 10n-14 = -12-12 -4n = -24 n = 6
How do you simplify 2n plus 2n?
4n
What is 4n plus 2 times 5n minus one?
20n2+6n-2 (4n + 2)(5n -1) This problem can be solved by FOILing. First, multiply the first terms to get 20n2 Next, multiply the outside terms to get -4n. Multiplication of the inside terms results in 10n. Combining -4n and 10n (they are like terms) is 6n. Then, multiply the last terms, to get -2. Combining these answers into one equation gives the answer of 20n2+6n-2.
What is 8m plus 4n-6m plus 9n?
8m + (4n - 6m) + 9n =8m + 4n - 6m + 9n =(8m - 6m) + (4n + 9n) =2m + 13n
What is the most force you get if you add a 6N force with a 4N force?
The total force you would get by adding a 6N force with a 4N force is 10N. This is because forces can be added together like numbers in mathematics to get the total force applied.
How many integers between 197 and 303 divisible by 4?
An=A¹+(n-1)d 300=200+(n-1)4 300-200=4n-4 100+4=4n ¼(104=4n) 26=n An=A¹+(n-1)d 300=200+(n-1)10 300-200=10n-10 100+10=10n ⅒(110=10n) 11=n Find the least common multiple of (4,10) 4 8 12 20 24 10 20 30 LCM=20 Then we are going to find the numbers between 200 and 300 that are divisible by 20. 200, 220, 240, 260, 280, 300 We have 6 numbers 26+11=37-6= 31 The answer is 31
How do you simplify n minus 10 plus 9n minus 3?
n - 10 + 9n - 3 n + 9n - 10 - 3 10n - 13
What can you make 0.50 using nickelsdime quarters?
q = quarters etc. 2q or 1q+2d+1n or 1q+1d+3n or 5d or 4d+2n or 3d+4n or 2d+6n or 1d+8n or 10n
What is the answer to 10n 40?
10n=40
What is 10n 40?
what is 10n=40
Which is the complete factorization of 2n-6n-36?
First we must collect and simplify 'like terms' 2n-6n-36. 2n-6n = -4n Therefore, -4n-36 Take out the greatest common factor. -4 (n+9) Ans = -4 (n+9)
