20n2+6n-2 (4n + 2)(5n -1) This problem can be solved by FOILing. First, multiply the first terms to get 20n2 Next, multiply the outside terms to get -4n. Multiplication of the inside terms results in 10n. Combining -4n and 10n (they are like terms) is 6n. Then, multiply the last terms, to get -2. Combining these answers into one equation gives the answer of 20n2+6n-2.
An=A¹+(n-1)d 300=200+(n-1)4 300-200=4n-4 100+4=4n ¼(104=4n) 26=n An=A¹+(n-1)d 300=200+(n-1)10 300-200=10n-10 100+10=10n ⅒(110=10n) 11=n Find the least common multiple of (4,10) 4 8 12 20 24 10 20 30 LCM=20 Then we are going to find the numbers between 200 and 300 that are divisible by 20. 200, 220, 240, 260, 280, 300 We have 6 numbers 26+11=37-6= 31 The answer is 31
To find the answer to the expression 7n - 2 - 3n + 4, you first simplify by combining like terms. Combine the 7n and -3n terms to get 4n. Then, combine the -2 and +4 terms to get +2. Therefore, the final answer is 4n + 2.
Start by factoring each part. If you find a common factor in the numerator and the denominator, eliminate it in both.
10n is basically 10 times something. Example: 10n = 100/n=10
The net force is the difference between the 10N falling object and the 4N of air resistance So you solve 10N-4N is 6N
10n+12 = 14n-12 10n-14 = -12-12 -4n = -24 n = 6
4n
20n2+6n-2 (4n + 2)(5n -1) This problem can be solved by FOILing. First, multiply the first terms to get 20n2 Next, multiply the outside terms to get -4n. Multiplication of the inside terms results in 10n. Combining -4n and 10n (they are like terms) is 6n. Then, multiply the last terms, to get -2. Combining these answers into one equation gives the answer of 20n2+6n-2.
8m + (4n - 6m) + 9n =8m + 4n - 6m + 9n =(8m - 6m) + (4n + 9n) =2m + 13n
The total force you would get by adding a 6N force with a 4N force is 10N. This is because forces can be added together like numbers in mathematics to get the total force applied.
An=A¹+(n-1)d 300=200+(n-1)4 300-200=4n-4 100+4=4n ¼(104=4n) 26=n An=A¹+(n-1)d 300=200+(n-1)10 300-200=10n-10 100+10=10n ⅒(110=10n) 11=n Find the least common multiple of (4,10) 4 8 12 20 24 10 20 30 LCM=20 Then we are going to find the numbers between 200 and 300 that are divisible by 20. 200, 220, 240, 260, 280, 300 We have 6 numbers 26+11=37-6= 31 The answer is 31
n - 10 + 9n - 3 n + 9n - 10 - 3 10n - 13
To find the answer to the expression 7n - 2 - 3n + 4, you first simplify by combining like terms. Combine the 7n and -3n terms to get 4n. Then, combine the -2 and +4 terms to get +2. Therefore, the final answer is 4n + 2.
q = quarters etc. 2q or 1q+2d+1n or 1q+1d+3n or 5d or 4d+2n or 3d+4n or 2d+6n or 1d+8n or 10n
10n=40
what is 10n=40