The first step would be to separate the square root of 80 into its component square roots: sqrt 4 x sqrt 20. sqrt 4 can simplify to 2, and sqrt 20 simplifies to sqrt 4 x sqr t5. sqrt 4 then simplifies to 2. Now it is 2x2x2xsqrt 5. The simplest form would then be 8 sqrt 5.
2 x √80
2 x √4 x √20
2 x 2 x √4 x √5
2 x 2 x 2 x √5
8 x √5
8√5
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(Square root of 5) times 4
Determine the perfect square factors of the term. Then, reduce 'em! √(80x²y) = √(16 * 5 * x² * y) = 4x√(5y)
No, the square root of 6400 is 80, and 3200 squared is 10240000.
160.000
√6400 = 80* * * * *OR -80