We have (2x + 4) / (3x + 6). First, we should factor both the numerator and denominator as much as possible. We get:
(2*(x + 2)) / (3*(x + 2))
Now, we can simplify the fraction by eliminating terms found in both the numerator and denominator - in this case x + 2. We get:
2/3.
It should be noted that this equivalence is only valid for x not equal to -2. When x is -2, the denominator becomes 0, and dividing by 0 is undefined.
3x(2x + 1) over (2x - 1)(2x + 1) Cancel out the 2x + 1 Answer: 3x/2x - 1
5x - 8a + 4a - 2x + a = 3x - 3a
3x^2 + x + 2x^2 = 5x^2 + x
simplify it, 7x-12=x+2+2x-3x 7x=2+12+3x-3x 7x=14 x=2
You can divide the integers in this case - 4 divided by 2 and 9 divided by 3. You would get 2 over x plus 3 over x. 4/2x + 9/3x = 2/x + 3/x = 5/x
3x(2x + 1) over (2x - 1)(2x + 1) Cancel out the 2x + 1 Answer: 3x/2x - 1
3x + 7y
5x - 8a + 4a - 2x + a = 3x - 3a
3x^2 + x + 2x^2 = 5x^2 + x
simplify it, 7x-12=x+2+2x-3x 7x=2+12+3x-3x 7x=14 x=2
3x-2y+9+9y-x = 2x+7y+9
You can divide the integers in this case - 4 divided by 2 and 9 divided by 3. You would get 2 over x plus 3 over x. 4/2x + 9/3x = 2/x + 3/x = 5/x
3x + 2x - 8x + 2x = -x
2x + 3x = 5x.
2x + 3x = 5x
3x2 + 2x - 8 = 3x2 + 6x - 4x - 8 = 3x(x + 2) - 4(x + 2) = (x + 2)(3x - 4).
Right, 3x-4x+9x-x1. 3x - x = 2x2. 9x-4x = 5x- 2x +5x = 7x