To solve the expression (0.3 \times 0.01 + 2.9), first multiply (0.3) by (0.01), which equals (0.003). Then, add (0.003) to (2.9), resulting in (2.903). Thus, the final answer is (2.903).
r + 11 + 8r = 29
v = -6
- 29 = - 4 = 5uadd 4 to each side- 29 + 4 = - 4 + 4 + 5u- 25 = 5udivide both sides integers by 5- 25/5 = (5/5)u- 5 = u========check in original equation- 29 = - 4 + 5(- 5)- 29 = - 4 - 25- 29 = - 4 + (- 25)- 29 = - 29=============checks
If I read right, then r= 4.5, so that (4)(4.5)(2)-7=29
2.9% is the same as 0.029 and 0.029*25 = 0.725
29% of 33 = 9.57 = 29% * 33 = 29%/100% * 33 = 0.29 * 33 = 9.57
r + 11 + 8r = 29
3*-7=29
v = -6
solve systems of up to 29 simultaneous equations.
- 29 = - 4 = 5uadd 4 to each side- 29 + 4 = - 4 + 4 + 5u- 25 = 5udivide both sides integers by 5- 25/5 = (5/5)u- 5 = u========check in original equation- 29 = - 4 + 5(- 5)- 29 = - 4 - 25- 29 = - 4 + (- 25)- 29 = - 29=============checks
It is e: 29
x-29 = 13+2x x-2x = 13+29 -x = 42 x = -42
Mulitply before adding. 57*29 is 1653, +82 is 1735
If I read right, then r= 4.5, so that (4)(4.5)(2)-7=29
17/29 = 24/n n*17/29 = 24 n*17 = 24*29 n = 24*29/17 n = 40.94117647
3x-7 = 14x-29 29-7 = 14x-3x 22 = 11x x = 2 Hope that helps!!;)