You can't just solve one side of the equation. You always have to have both sides of the equal sign in order to manipulate the terms.
If you have an equation like 10a + 5b=0, you can now solve for one of the terms (a or b), for example, b=10a/5 and a=-5b/10. Once you have solved for one term, you can plug it back into the equation and solve for real values.
In this particular equation, a=-1/2b so by putting any value in for b (say 2), you get a definite value for a (-1) but there are an infinite number of such values.
10a+7b undefined variables cannot be determined
10a + 5b
-86
here is how you go about solving it first write down the question 3b+4+5b-1 then change arrangement so that it looks like this 3b+5b+4-1 then solve 8b+3
Factor completely and check mentally 10a^2+20a
10a+7b undefined variables cannot be determined
10a + 5b
10a - 5b = 25 So 5b = 10a - 25 and hence b = 2a - 5
The expression is simplified to: 12f-(10a+5b)
The only common factor of 10a and 5b is a 5. So the factored form will be something like: 5(2a _ b) assuming the _ is filled in with the proper operation (+ - * / etc.). If the original expression is 10a + 5b, the answer would be 5(2a + b).
5b + 3 = 10 - 3 - 3 5b = 7 5b/5 7/5 b= 1.5 There you go !
to solve this expression: 10a-4(a+2) -> 10a-4(a)-4(2) -> 10a-4a-8 -> 6a-8
the answer
-86
here is how you go about solving it first write down the question 3b+4+5b-1 then change arrangement so that it looks like this 3b+5b+4-1 then solve 8b+3
Factor completely and check mentally 10a^2+20a
10a+a