Q: How do you solve 1 minus 7n equals 15 minus 5n?

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5n+15 = 25 5n = 25-15 5n = 10 n = 2

5n + 15 = 25 you subtract 15 from both sides then you get 10 then divided 5n by 10 you get 2n

5n-2+2=4n 5n=4n n=0

-5n+9=-46 -5n+9-9=-46-9 -5n=-55 -5n/-5=-55/-5 n=11

In the equation 5n-11=4n+20, n is equal to 31.

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9-5n+1 = 15 -5n = 15-9-1 -5n = 5 Divide both sides of the equation by -5 to find the value of n: n = -5

5n+15 = 25 5n = 25-15 5n = 10 n = 2

5n + 15 = 25 you subtract 15 from both sides then you get 10 then divided 5n by 10 you get 2n

5n-25 = 10 5n = 10+25 5n = 35 n = 7

It is: 2n^2 -5n -42 equals (2n+7)(n-6) when factored

5n-2+2=4n 5n=4n n=0

9 - 5n + 1 = 15 -5n = 15 - 10 n = -5/5 n = -1

-5n+9=-46 -5n+9-9=-46-9 -5n=-55 -5n/-5=-55/-5 n=11

n=8

In the equation 5n-11=4n+20, n is equal to 31.

Whatever your value of n is, you need to multiply it by 5 and then add 2 to get your answer. Below is how to solve it algebraically: 5n+2 = 0 (it needs to be equal to something in order to solve it, so I assumed that it equals zero) 5n = -2 n = -2/5

5n-5, because its the 5 time table (called 5n) minus 5 each time