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20x^2 + 27x + 9 = 0

20x^2 + 15x +12x + 9 = 0

5x(4x + 3) + 3(4x + 3) = 0

(5x + 3)(4x + 3) = 0

So either (5x + 3) = 0 which yields x = -3/5 or (4x + 3) = 0 which yields x = -3/4

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Q: How do you solve 20x2 plus 27x plus 9 equals 0?
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