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(2x-1)*(3x+5)=5

Use foil's method. First Outside Inside Last for multiplying

the equation turns out to this

(2x*3x)+(2x*5)+-(1*3x)+-(1*6)=5

Solve within the parentheses.

6x2+ 10x+-3x+-6=5

Continue to solve

6x2+7x+-6=5

You need to make =5 to =0


6x2+7x+-6+-5=5-5


6x2+7x+-11=0


quadratic formula is x=[-b +- {b^2*(-4ac)^2}]/2a
there are two equations to solve. the number and the opposite of a number











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Q: How do you solve 2x-1 times 3x plus 5 equals 5?
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