Q: How do you solve 2x2 equals 8x?

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2x2 = 8x x = 8x/2x x = 4 Check: 2(4)2 = 8(4) 2(16) = 32 32 = 32

x3 + 2x2 - 8x + 5 = 0 x(2x - 8) + 5 = 0

2x2 - 8x + 3 = 0 needs to be solved using the quadratic formula.x = (4 + sqrt(10))/2 or x = (4 - sqrt(10))/2

8x - 7.2Divide each side by 8:x = 0.9

Yes. 8x - 11 = 69 so 8x = 80 or x = 10.

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2x2 = 8x x = 8x/2x x = 4 Check: 2(4)2 = 8(4) 2(16) = 32 32 = 32

-1/2

x3 + 2x2 - 8x + 5 = 0 x(2x - 8) + 5 = 0

2x2 - 8x + 3 = 0 needs to be solved using the quadratic formula.x = (4 + sqrt(10))/2 or x = (4 - sqrt(10))/2

I'm sorry but I can't solve that problem. B(

8x + -2 = 10 8x = 12 x = 1.5

I'm an orange!

8x - 7.2Divide each side by 8:x = 0.9

Yes. 8x - 11 = 69 so 8x = 80 or x = 10.

6x-20 = 8x 6x-8x = 20 -2x = 20 x = -10

You don't solve this. It is an identity. 8X - 14 = 8X - 14 add 14 to each side 8X = 8X divide both sides integers by 8 X = X =============X can be any number you want.

-8x + 6 = -58 -8x = -64 x= -64/-8 x = 8