3x-28-5x=5x+13
Let us first solve the variables
-2x-28=5x+13
Transposing -28 to Right hand side
-2x=5x+13+28
-2x=5x+41
Transposing 5x to left hand side
-2x-5x=41
-7x=41 equation 1
x=41/-7
x=-41/7
Hence the required answer is -41/7.
You can verify it by substituting the value of x in the given equation. If Right hand side is equal to Left hand side the answer is right.
Let us verify
Substituting the value of x=-41/7 in the given equation1
-7(-41/7)=41
-7 X -41/7 =41
41=41
LHS=RHS
Hence Verified
5
12 + 5 equals...
To solve for x, we'd have to know what this expression equals.
Set up the equation and solve: 13 = 7 + s (next subtract 7 from each side of the equation to solve for s) 6 = s
(x - 3)(x + 5)
5
X +13 equals 22, X equals nine
12 + 5 equals...
To solve for x, we'd have to know what this expression equals.
If: 2a+13 = 5a+1 Then: a = 4
7+6
Set up the equation and solve: 13 = 7 + s (next subtract 7 from each side of the equation to solve for s) 6 = s
6+8=14
(x - 3)(x + 5)
13=e+2 11=e (subtract 2 from each side)
6x + 8 = 13, 6x = 13 - 8, 6x = 5, x = 5/6
3h+13 = 7 3h = 7-13 3h = -6 h = -2