3x² + 10x = 8 Rewrite as: 3x² + 10x - 8 = 0
The only way to get 3x² is 3x and x
(3x + -- ) (x + --)
The factors of 8 are {1 2 4 8} so the answers must be a pair of them.
With 4 factors, and a negative sign (the -8), there are only 8 ways this can be written:
(3x + 1)(x - 8) = 3x² - 23x - 8
(3x + 2)(x - 4) = 3x² -10x - 8 (almost)
(3x + 4 )(x - 2) = 3x² - 8x - 8
(3x + 8)(x - 1) = 3x² +5x - 8
(3x - 1)(x + 8) = 3x² +23x - 8
(3x - 2)(x + 4) = 3x² + 10x -8 ◄ Success!
(3x - 4)(x + 2) = 3x² +2x - 8
(3x - 8)(x + 1) = 3x² -5x - 8
Trial and error, error, error, is the key to this kind of problem. Seeing the -10x early can point you to see that maybe changing the signs can work. ■
You find x. Oh! There it is!! ^ See?
(x + 8)(x + 2)
12x - 6 = 10x +2 12x - 10x = 2 + 6 2x = 8 x = 4
The roots are -3 and -7. Easily by factoring and setting each factor equal to 0. The factors are x + 7 and x +3.
5x/x-2
10x+7=(-3) 10x=(-10) x=(-1)ans
x=-8
You find x. Oh! There it is!! ^ See?
(x + 8)(x + 2)
12x - 6 = 10x +2 12x - 10x = 2 + 6 2x = 8 x = 4
There is no symbol between 7x and 31. Please resubmit using words eg "plus", "equals" etc.
The roots are -3 and -7. Easily by factoring and setting each factor equal to 0. The factors are x + 7 and x +3.
5x/x-2
10x=x 9x=0 x=0
x - 10x = 9x, so 9x + 3 = 0, so 9x = -3 so x = -1/3
11x = 10x-19 Subtact 10x fromboth sides:- x = -19
12x + 9 = 10x + 1 Subtract 10x from both sides: 2x + 9 = 1 Sutract 9 from both sides: 2x = - 8 Divide both sides by 2: x = -4