i dont know what you are trying to solve for, but if you are solving for x and y. u have to......
3x-4y=4
x= 4/3..... 1.33
y=4/-4...... -1
x = 4 and y = 0
3x - 4y = 10-3x - 4y = 8 -> add line 1 to line 2 3x - 4y = 100x - 8y = 18 -> -8y = 18 -> y = -18/8 = -9/4 -> 3x - 4*(-9/4) = 10 -> 3x + 9 = 10 -> 3x = 1 -> x = 1/3
3x+4y = 4 4y = -3x+4 y = -3/4x+1 So the slope is -3/4 and the intercept is 1
(2, -1)
3x + 4y - 4 = 0 y = -2 3x + 4(-2) - 4 = 0 3x - 8 - 4 = 0 3x = 12 x = 4 (4,-2)
x = 4 and y = 0
3x - 4y = 10-3x - 4y = 8 -> add line 1 to line 2 3x - 4y = 100x - 8y = 18 -> -8y = 18 -> y = -18/8 = -9/4 -> 3x - 4*(-9/4) = 10 -> 3x + 9 = 10 -> 3x = 1 -> x = 1/3
3x+4y = 4 4y = -3x+4 y = -3/4x+1 So the slope is -3/4 and the intercept is 1
4y = 3x+11 or as y = 3/4x+11/4
3x - 4y = 8Solve for x:3x = 4y + 8x = 4/3y + 8/3Solve for y:-4y = -3x + 8y = 3/4x - 2
(2, -1)
3x - 2y = 20 Substitute x = 4y into this equation: 3(4y) - 2y = 20 ie 12y - 2y = 20 10y = 20 so that y = 2 and then x = 4y gives x = 2*4 = 8
3x + 4y - 4 = 0 y = -2 3x + 4(-2) - 4 = 0 3x - 8 - 4 = 0 3x = 12 x = 4 (4,-2)
1
3x - 4y -16 = 0 Algebraically rearrange to to make '4y' the subject. Hence 4y = 3x - 16 ( Note the change of sign, on taking the '4y' across the equals to replace the zero. ). Divide both sides by ;4; y = (3/4)x - 16/4 y = ( 3/4)x - 4 Hence the slope is ' 3/4 ' and the y-intersect is '-4'. NB For all straight line of the form y = mx + c 'm' is the slope , and 'c' is the y-intersect. All you need to do on being given linear equations of the form px + ny + c = o or px + c = ny or px + ny = c etc. is to algebraically rearrange into the form of y = mx + c , making sure you change the signs correctly, and then dividing both sides by the coefficient of 'y' .
2x+3xy-4y=10to solve for yyour objective will be to get y by itself on one side of the equal signyou first subtract 2x to get the terms with y variables on one side3xy-4y=10-2xthen undistribute the y from the two terms to get one yy(3x-4)=10-2xnow divide 3x-4y=(10-2x)/(3x-4)theres your answer
(0,-4)