How do you solve 3y3 - 14y2 - 5y equals 0?

Answer 1

3Y3 - 14Y2 - 5Y = 0

factor out a Y

Y(3Y2 - 14Y - 5) = 0

we know one answer is

Y = 0

------------so, to find other answer(s), the quadratic formula here

3Y2 - 14Y - 5 = 0

Y = - b (+/-) sqrt(b2 - 4ac)/2a

a = 3

b = - 14

c = - 5

Y = - (- 14) (+/-) sqrt[(-14)2 - 4(3)(- 5)]/2(3)

Y = 14 (+/-) sqrt(196 + 60)/6

Y = 14 (+/-) sqrt(256)/6

Y = [14 (+/-) 16]/6

Y = 5

Y = - 1/3

so, you answers are

Y = ( - 1/3, 0, 5)