This is impossible as the variables are different
2x^2y^3(4x^2 - 3xy + 1)
Add 4x + 2x = 6x + 4 = 6x + 4
y=4x-8y=2x+10Substitute (4x-8) for y in the second equation and solve for x:4x-8=2x+102x=18x=9Now solve for y:y=4(9)-8=28(9,28)
2x + 2x + 146 + 26 = 172 4x + 172 = 172 4x = 0 x = 0
This is impossible as the variables are different
2x^2y^3(4x^2 - 3xy + 1)
4
(2x + 1)(4x^2 - 2x + 1)
multiply the base number and add the two exponets together
-2x = -4x + 24 -2x + 4x = 24 2x = 24 x = 24/2 x = 12
Add 4x + 2x = 6x + 4 = 6x + 4
3x - 5x + 4x = -2x +4x = 2x
y=4x-8y=2x+10Substitute (4x-8) for y in the second equation and solve for x:4x-8=2x+102x=18x=9Now solve for y:y=4(9)-8=28(9,28)
4x+2=2x-102x=-12 x=-6
8x2
-1-2x-4x=19-6x-1 = -19x = 3