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This is impossible as the variables are different
2x^2y^3(4x^2 - 3xy + 1)
Add 4x + 2x = 6x + 4 = 6x + 4
y=4x-8y=2x+10Substitute (4x-8) for y in the second equation and solve for x:4x-8=2x+102x=18x=9Now solve for y:y=4(9)-8=28(9,28)
The answer is (2x^2+3)(4x+1)