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OK, SO 4x = 12x + 32.
SO 4x -12x-12x-12x+32 (subtract 12x from each side to get x on one side)
SO -8x = 32 (simplify)
SO -1 (-8x) = 32 (-1) (multiply each side by -1)
SO 8x -32 (simplify)
SO 8x / 8 = -32/8 (divide each side by eight (8) to get ""X"" by itself)
SO x= -4
SO x = -4.
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What is the answer to 12 x plus 16 y equals when x equals 1 and y equals 2?
You plug in the values of x and y and solve 12x + 16y = ? 12(1) + 16(2) = 12 + 32 = 44
4x plus 32 equals -4x plus 16 x equals?
4x+32=-4x+16x4x+32=12x-4x -4x32=8x/8 /84=x
Y equals 5-2x and 4x plus 6y equals -2 solve by substitution?
y = 5 - 2x so 4x + 6(5 - 2x) = -2 ie 4x + 30 - 12x = -2 Subtract 30 from each side: 4x - 12x = -32 ie -8x = -32 so x = 4 and y = -3
Solve 12c plus c2 plus 32 equals 0?
c= -2 2/7 OR -2.285714
4x plus 32 equals 12x - 8?
Are you trying to find x? If so, get all x's to one side, 32=8x-8, then get x alone... 40= 8x then divide by 8... 5=x So at x=5, 4x+32=12x-8
