How do you solve 5 raised to 8-2x equals 25?

Answer 1

Use natural logs.

5^(8-2X) = 25

ln5^(8-2X) = ln25

8-2X ln5 = ln25

8-2X = ln25/ln5

8-2X = 2

subtract 8 from each side

-2X = -6

divide each side by -2

X = 3

check

5^(8-3(2)) = 25

5^2 = 25

25 = 25

checks