The idea is to change the equation in such a way that the "x" remains isolated (alone) on one side of the equation. In this case, first add 1 to both side of the equation. This will eliminate the "-1" on the left. Then, divide both sides by 5. This will eliminate the 5, and leave the "x" alone. Whatever is left on the right is the solution.
5x+1=20 5x=20-1 5x=19 5x/5=19/5 x=19/5
x+2y = -1 and 5x-4y = 16 Solving the simultaneous equations gives: x = 2 and y = -1.5
x=8
7x -3 = 5x + 1 solve for xadd three to both sides7x = 5x + 4subtract 5x from both sides2x = 4divide both sides by 2x = 2
y = 5x + 1 is nota direct variation.y = 5x + 1 is nota direct variation.y = 5x + 1 is nota direct variation.y = 5x + 1 is nota direct variation.
5x - 1 = 24 5x - 1 + 1 = 24 + 1 5x = 25 5x/5 = 25/5 x = 5
-5x+1 = 6x -5x-6x = -1 -11x = -1 x = 1/11
5x+1=20 5x=20-1 5x=19 5x/5=19/5 x=19/5
If: 5x+1 = 21 Then: 5x = 21-1 => 5x = 20 Divide both sides by 5 and so x = 4
y = 2x -1 y = 5x -13 So: 5x -13 = 2x -1 5x -2x = 13 -1 3x = 12 x = 4 and by substituting y = 7
x+2y = -1 and 5x-4y = 16 Solving the simultaneous equations gives: x = 2 and y = -1.5
x=8
5x + 9 = 4Subtract 9 from each side:5x = -5Divide each side by 5:x = -1
7x -3 = 5x + 1 solve for xadd three to both sides7x = 5x + 4subtract 5x from both sides2x = 4divide both sides by 2x = 2
y = 5x + 1 is nota direct variation.y = 5x + 1 is nota direct variation.y = 5x + 1 is nota direct variation.y = 5x + 1 is nota direct variation.
7X-1=9+5X. add 1 to both sides 7X=10+5X. Subtract 5X and get 2X=10 divide by 2 and x=5
2x + 5x - 1 = 9x 7x - 1 = 9x -1 = 9x - 7x -1 = 2x -1/2=x