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The idea is to change the equation in such a way that the "x" remains isolated (alone) on one side of the equation. In this case, first add 1 to both side of the equation. This will eliminate the "-1" on the left. Then, divide both sides by 5. This will eliminate the 5, and leave the "x" alone. Whatever is left on the right is the solution.
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How do you solve 5x plus 1 equals 20?
5x+1=20 5x=20-1 5x=19 5x/5=19/5 x=19/5
X plus 2y equals -1 5x - 4y equals 16?
x+2y = -1 and 5x-4y = 16 Solving the simultaneous equations gives: x = 2 and y = -1.5
What is the answer to this math problem 5x plus 1 equals 41 solve for x?
x=8
7x-3 equals 5x plus 1?
7x -3 = 5x + 1 solve for xadd three to both sides7x = 5x + 4subtract 5x from both sides2x = 4divide both sides by 2x = 2
How do you solve the direct variation y equals 5x plus 1?
y = 5x + 1 is nota direct variation.y = 5x + 1 is nota direct variation.y = 5x + 1 is nota direct variation.y = 5x + 1 is nota direct variation.
