answersLogoWhite

0

Subjects>Math>Math & Arithmetic

How do you solve 6x-4y equals 54 -9x plus 2y equals -69 using substitution?

User Avatar

Anonymous

∙ 13y ago
Updated: 12/24/2022

-9x + 2y = -69

So 2y = 9x - 69

The other equation can be written as

6x - 4y = 54 or 6x - 2*2y = 54

Substituting for 2y gives

6x - 2*(9x - 69) = 54

6x - 18x + 138 = 54

12x = 84

x = 7

and then 2y = 9x - 69 = 9*7 - 69 = 63-69 = -6

so that y = -3

User Avatar

Wiki User

∙ 13y ago
Copy

What else can I help you with?

Continue Learning about Math & Arithmetic
Related Questions
Trending Questions
What is 33 percent of 27? How much is 1.25kg at 2 per kilogram? What was the warning that God gave to Adam? Two numbers that add up to zero? How many digits are in 100000? What plus what is 140? How do you promote positive behavior in schools? How do you solve problem related to square root? Is the routing number the same as a national clearing code? What is yards in measurement? What is the distance from negative three comma one to negative one comma five? What Is 70 percent Of 780? What is an abrical expression of b plus 14? If you vertically shift the linear parent function F(x) x down six units what is the equation of the new function? How do you measure 50grams of honey? What website has the McDougal Littell Pre-Algebra online for free? What is the length of the diameter whose end points are -5 4 and 3 -6? What are two equivalent fractions to 4 28? What is the density of pebbles? What is 893635 plus 87654?

Resources

Leaderboard All Tags Unanswered

Top Categories

Algebra Chemistry Biology World History English Language Arts Psychology Computer Science Economics

Product

Community Guidelines Honor Code Flashcard Maker Study Guides Math Solver FAQ

Company

About Us Contact Us Terms of Service Privacy Policy Disclaimer Cookie Policy IP Issues
Answers Logo
Copyright ©2025 Answers.com. All Rights Reserved. The material on this site can not be reproduced, distributed, transmitted, cached or otherwise used, except with prior written permission of Answers.