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It has two variables (X and Y), so can not have a single salvation. Thus, salvation will be a set of (X;Y) pairs (that forms line in a Cartesian coordinate system:
6x+2y=14
2y=14-6x
y=(14-6x)/2
y=7-3x
The general form of a line is y=kx+b, where k and b are constants. In our case we a have a line described by y=7-3x
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X plus 2y equals 11 and x equals 14-2y?
x = 11 - 2y and 14 - 2y. This means that 11 = 14. Is there a typo in the question?
How do you solve 4y plus 2 equals 2y plus 6?
4y+2 = 2y+6 4y-2y = 6-2 2y = 4 y = 2
How do you solve 2x plus y equals 0 and 4x plus 2y equals 0?
many solutions
What would you do to solve 2y plus 4 equals 3y?
2y + 4 = 3ySubtract 2y from both sides:4 = ywhew
What is 3x plus 2y equals 6 solve for y?
3x+2y=6 2y=-3x+6 y=-1.5x+3
2y-9x equals 14 solve for y?
2y - 9x = 14 2y = 14 + 9x y = (14 + 9x) / 2
X plus 2y equals 11 and x equals 14-2y?
x = 11 - 2y and 14 - 2y. This means that 11 = 14. Is there a typo in the question?
How do you solve 2y equals 4x plus 4?
2y = 4x + 4y = 2x + 2
W plus x equals 2y plus z for x?
you can not solve this equation
How do you solve 4y plus 2 equals 2y plus 6?
4y+2 = 2y+6 4y-2y = 6-2 2y = 4 y = 2
How do you solve 2x plus y equals 0 and 4x plus 2y equals 0?
many solutions
What would you do to solve 2y plus 4 equals 3y?
2y + 4 = 3ySubtract 2y from both sides:4 = ywhew
-6y plus 14 plus 4y equals 32?
-6y + 14 + 4y = 32-2y = 32 - 14-2y = 18y = - 9
What are the solutions to the simultaneous equation of 3x plus 2y equals 5x plus 2y equals 14 showing work?
If: 3x+2y = 5x+2y = 14 Then: 3x+2y = 14 and 5x+2y =14 Subtract the 1st equation from the 2nd equation: 2x = 0 Therefore by substitution the solutions are: x = 0 and y = 7
How do you solve this equation 3x plus 2y equals 12 solve for y?
3x + 2y = 12 ie 2y = 12 - 3x so y = 6 - 3x/2
4x plus 6y equals 14 -2x plus 2y equals -2?
(2, 1)
What is 3x plus 2y equals 6 solve for y?
3x+2y=6 2y=-3x+6 y=-1.5x+3
