I understand this equation to be 7w = 42. The principle we use for solving equations like this one is that we can do the same thing to both sides of the equation and the equation will still be _true_.
We want the 'w' by itself. This implies ridding the left side of the 7. We can turn it into a one (1) by dividing it by 7. But if we do that to the left side of the equation then we must also do that to the right side.
7w/7 = 42/7
1w = 6 or w = 6, the result.
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7w = 42
Divide both sides by '7'.
Hence
7w/7 = 42/7
Cancel down by '7'
w = 6 The answer!!!!
4w - 2 = -7w11w - 2 = 011w = 2w = 2/11
7W + 4 - 3W = 15gather the w's together4W + 4 = 15subtract 4 from each side4W = 11divide each sides integers by 4W = 11/4================checks
56w2 + 17w - 3 = 56w2 + 24w - 7w - 3 = 8w(7w + 3) - 1(7w + 3) = (7w + 3)(8w - 1)
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