8x2 + 16x + 8 = 0
8x2 + 16x + 8 = 8*(x2 + 2x + 1) = 8*(x + 1)2
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x=5
To factor the equation ( x^3 + 8x^2 + 16x = 0 ), first, rewrite it as ( x^3 + 8x^2 + 16x + 16 = 16 ). By factoring out the common term ( x ), we get ( x(x^2 + 8x + 16) = 0 ). The quadratic ( x^2 + 8x + 16 ) can be factored as ( (x + 4)^2 ). Therefore, the factored form is ( x(x + 4)^2 = 0 ).
the roots are 1, - 1/3, - 3 1/2 and 3 1/2
8x2 + 16x + 8 = 8*(x2 + 2x + 1) = 8*(x + 1)2
Please do not remove this question from Inappropriate or split any alts from it. Thanks!
24x4 + 16x² - 8 = 8(3x4 + 2x² - 1) = 8(x² + 1)(3x² - 1).
x=5
15 = 8x2 - 14x; whence, 8x2 - 14x - 15 = (2x - 5)(4x + 3) = 0. Therefore, x = 5/2 or -3/4.
16.
To factor the equation ( x^3 + 8x^2 + 16x = 0 ), first, rewrite it as ( x^3 + 8x^2 + 16x + 16 = 16 ). By factoring out the common term ( x ), we get ( x(x^2 + 8x + 16) = 0 ). The quadratic ( x^2 + 8x + 16 ) can be factored as ( (x + 4)^2 ). Therefore, the factored form is ( x(x + 4)^2 = 0 ).
It is: 25-4(8*6) = -167
the roots are 1, - 1/3, - 3 1/2 and 3 1/2
(4x + 3)(2x - 1) so x = -0.75 or 0.5
You could try dividing both numerator and denominator by 8x2 .
8x2 DUH