(-x)2 = 3=> -x = ±√3=> x = -√3 and x = √3
3x^2 + 5x - 8 = 0 + 8 + 8 3x^2 + 5x = 0 8x ^2 = 0
3x2 - 11x - 4 = 0(3x + 1)(x - 4)x = -1/3 and 4
5
Add 2.9 to both sides. y = 8.2
It is: 9-4 = 5
(-x)2 = 3=> -x = ±√3=> x = -√3 and x = √3
3x^2 + 5x - 8 = 0 + 8 + 8 3x^2 + 5x = 0 8x ^2 = 0
By factoring I get x-3 divided by x+3
3x2 - 11x - 4 = 0(3x + 1)(x - 4)x = -1/3 and 4
If you are looking for the zeros of this function: x = -2 plus or minus 2 X the square root of 5.
5
Forty-three minus nine equals 34.
Add 2.9 to both sides. y = 8.2
Three fourths minus three sixths equals one fourth
If you mean: 10ac -x/11 = -3 then a as the subject is a = (-33+x)/110c
3 squared=9 3 squared=3*3 3*3=9