Compound Interest is the interest which gets compounded in Specified time periods..
The formula for solving Compound Interest problems is as follows:
A=P(1+R/100)n
Where,
A= Amount after Including Compound Interest
P= Principle
R= Rate %
n= Time Period
For Calculating Compound Interest:
CI=A-P
Where,
CI= COmpound Interest
A= Amount
P= Principle
For Eg: If Rs 1000 is lend @ 10% Compounded Anually for 2 years, then calculation will be done as follows:
A= 1000 (1+10/100)2
= 1000 (1.1)2
= Rs 1210
& Compound Interest will be A-P i.e. Rs 1210-1000= Rs 210.
Also, Whenever Compounded Half Yearly or Compounded Quarterly is given, the rate will be divided by 2 & 4 respectively & time period will be multiplied by 2 & 4 respectively.
For Eg: if in the above eg, Compounded Half yearly is given, then
take R= 5%, n = 4 years (4 half years in 2 years)
& if Compounded Quarterly is given, then,
take R= 2.5%, n= 8 (8 quarters in 2 years)
A man Iinvests 5000 for 2 years at compound intrest. After 1 year his money amounts to 5150. Find the intrest for the second year.
Showing the question would help to solve it.
Do you have a specific problem for this question? Because when a question asks for you to "solve for p" they will put it in the form of an algebraic equation, for example, 1 + p = 5 .. In that case you are trying to find out all the values for p which would fit in, here being 4.
This is called Simple Interest. The formula is A= P(1+rt) where P is the Principal, r is the Rate and t the time in years. eg $1000 at 4% over 5 years A=1000 (1+0.04*5) where * means multiply = 1000 (1.20) = $1200
That depends what you want to "solve" for - in other words, what the question is. For example, whether you want to:* Convert from hexadecimal to decimal* Convert from decimal to hexadecimal* Count in hexadecimal* Add hexadecimal numbers* etc.
It depends on which compound interest formula you mean. Refer to the Wikipedia Article on "Compound Interest" for the correct terminology.
A man Iinvests 5000 for 2 years at compound intrest. After 1 year his money amounts to 5150. Find the intrest for the second year.
Oh, what a lovely question we have here! To find the time it takes for 2700 to yield the same interest as 2250 in 4 years, we simply need to compare the interest rates. Since the interest rates are different, we can use a formula called the "interest formula" to solve for the time needed. Let's embrace the joy of solving this together!
Spectroscopy
Showing the question would help to solve it.
sg like this: input= 100.0; years= 7; percent= 4; output = input * pow (1.0 + percent/100.0, years);
Actually whenever we ask any question related to interest , we always require the time period also . On how much long time period , you want the interest . But , if time is not mentioned in question , then by default we take it as one year . So , we can solve it by using the formula I=(P*R*T)/100 . So , the answer of this quetion is 51.4368 .
3/0=? solve that one w/o creating a black hole
Homogeneous means "the same". As for the rest, it might help to have the question.
I will be able to answer this question if you give me a equation as an example.
Do you have a specific problem for this question? Because when a question asks for you to "solve for p" they will put it in the form of an algebraic equation, for example, 1 + p = 5 .. In that case you are trying to find out all the values for p which would fit in, here being 4.
This is called Simple Interest. The formula is A= P(1+rt) where P is the Principal, r is the Rate and t the time in years. eg $1000 at 4% over 5 years A=1000 (1+0.04*5) where * means multiply = 1000 (1.20) = $1200