Compound Interest is the interest which gets compounded in Specified time periods..
The formula for solving Compound Interest problems is as follows:
A=P(1+R/100)n
Where,
A= Amount after Including Compound Interest
P= Principle
R= Rate %
n= Time Period
For Calculating Compound Interest:
CI=A-P
Where,
CI= COmpound Interest
A= Amount
P= Principle
For Eg: If Rs 1000 is lend @ 10% Compounded Anually for 2 years, then calculation will be done as follows:
A= 1000 (1+10/100)2
= 1000 (1.1)2
= Rs 1210
& Compound Interest will be A-P i.e. Rs 1210-1000= Rs 210.
Also, Whenever Compounded Half Yearly or Compounded Quarterly is given, the rate will be divided by 2 & 4 respectively & time period will be multiplied by 2 & 4 respectively.
For Eg: if in the above eg, Compounded Half yearly is given, then
take R= 5%, n = 4 years (4 half years in 2 years)
& if Compounded Quarterly is given, then,
take R= 2.5%, n= 8 (8 quarters in 2 years)
A man Iinvests 5000 for 2 years at compound intrest. After 1 year his money amounts to 5150. Find the intrest for the second year.
Showing the question would help to solve it.
Do you have a specific problem for this question? Because when a question asks for you to "solve for p" they will put it in the form of an algebraic equation, for example, 1 + p = 5 .. In that case you are trying to find out all the values for p which would fit in, here being 4.
This is called Simple Interest. The formula is A= P(1+rt) where P is the Principal, r is the Rate and t the time in years. eg $1000 at 4% over 5 years A=1000 (1+0.04*5) where * means multiply = 1000 (1.20) = $1200
That depends what you want to "solve" for - in other words, what the question is. For example, whether you want to:* Convert from hexadecimal to decimal* Convert from decimal to hexadecimal* Count in hexadecimal* Add hexadecimal numbers* etc.
It depends on which compound interest formula you mean. Refer to the Wikipedia Article on "Compound Interest" for the correct terminology.
A man Iinvests 5000 for 2 years at compound intrest. After 1 year his money amounts to 5150. Find the intrest for the second year.
Oh, what a lovely question we have here! To find the time it takes for 2700 to yield the same interest as 2250 in 4 years, we simply need to compare the interest rates. Since the interest rates are different, we can use a formula called the "interest formula" to solve for the time needed. Let's embrace the joy of solving this together!
Spectroscopy
sg like this: input= 100.0; years= 7; percent= 4; output = input * pow (1.0 + percent/100.0, years);
Showing the question would help to solve it.
Actually whenever we ask any question related to interest , we always require the time period also . On how much long time period , you want the interest . But , if time is not mentioned in question , then by default we take it as one year . So , we can solve it by using the formula I=(P*R*T)/100 . So , the answer of this quetion is 51.4368 .
3/0=? solve that one w/o creating a black hole
Homogeneous means "the same". As for the rest, it might help to have the question.
I will be able to answer this question if you give me a equation as an example.
Do you have a specific problem for this question? Because when a question asks for you to "solve for p" they will put it in the form of an algebraic equation, for example, 1 + p = 5 .. In that case you are trying to find out all the values for p which would fit in, here being 4.
This is called Simple Interest. The formula is A= P(1+rt) where P is the Principal, r is the Rate and t the time in years. eg $1000 at 4% over 5 years A=1000 (1+0.04*5) where * means multiply = 1000 (1.20) = $1200