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You could multiply each term on both sides of the equation by a number which would make each term have integer coefficients. Or convert the decimal to a fraction equivalent.
Example: y = 0.2x + .25, You can multiply by 100 to get 100y = 20x + 25, or you could multiply by 20, to get 20y = 4x + 5, or just convert it to y = x/5 + 1/4
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Solve linear equations with complex coefficients on both sides?
You would solve them in exactly the same way as you would solve linear equations with real coefficients. Whether you use substitution or elimination for pairs of equations, or matrix algebra for systems of equations depends on your requirements. But the methods remain the same.
How do you solve equations involving fractional coefficients?
multiply the whole equation by the number in the denominator
How do you solve decimals?
Decimals are simply a way to express numbers. There is nothing to solve!
How do you solve a system of equation with 3 equations and 3 variables?
If you know matrix algebra, the process is simply to find the inverse for the matrix of coefficients and apply that to the vector of answers. If you don't: You solve these in the same way as you would solve a pair of simultaneous linear equations in two unknowns - either by substitution or elimination. For example, change the subject of one of the equations to express one of the variables in terms of the other two. Substitute this value into the other two equations. When simplified, you will have two linear equations in two variables.
How do you solve these equations?
Tell me the equations first.
