You could multiply each term on both sides of the equation by a number which would make each term have integer coefficients. Or convert the decimal to a fraction equivalent.
Example: y = 0.2x + .25, You can multiply by 100 to get 100y = 20x + 25, or you could multiply by 20, to get 20y = 4x + 5, or just convert it to y = x/5 + 1/4
You would solve them in exactly the same way as you would solve linear equations with real coefficients. Whether you use substitution or elimination for pairs of equations, or matrix algebra for systems of equations depends on your requirements. But the methods remain the same.
multiply the whole equation by the number in the denominator
Decimals are simply a way to express numbers. There is nothing to solve!
If you know matrix algebra, the process is simply to find the inverse for the matrix of coefficients and apply that to the vector of answers. If you don't: You solve these in the same way as you would solve a pair of simultaneous linear equations in two unknowns - either by substitution or elimination. For example, change the subject of one of the equations to express one of the variables in terms of the other two. Substitute this value into the other two equations. When simplified, you will have two linear equations in two variables.
Tell me the equations first.
You would solve them in exactly the same way as you would solve linear equations with real coefficients. Whether you use substitution or elimination for pairs of equations, or matrix algebra for systems of equations depends on your requirements. But the methods remain the same.
multiply the whole equation by the number in the denominator
Not necessarily, but often it is simpler to convert fractions into decimals to solve the equation.
Create a matrix of the coefficients of each equation. The solutions to the equations should make up the rightmost column of the matrix. Then, row reduce the matrix until you are able to rewrite the equations and solve them. The matrix should be a 4x5 matrix (4 rows and 5 columns) for four equations with four variables. This is known as a system of equations.
Write each equations in popular form. ... Make the coefficients of one variable opposites. ... Add the equations ensuing from Step two to remove one variable. Solve for the last variable. Substitute the answer from Step four into one of the unique equations.
Decimals are simply a way to express numbers. There is nothing to solve!
13 cards.
If you know matrix algebra, the process is simply to find the inverse for the matrix of coefficients and apply that to the vector of answers. If you don't: You solve these in the same way as you would solve a pair of simultaneous linear equations in two unknowns - either by substitution or elimination. For example, change the subject of one of the equations to express one of the variables in terms of the other two. Substitute this value into the other two equations. When simplified, you will have two linear equations in two variables.
Equations can have as many variables as you want, however to solve an equation you need as many equations as there are unknowns. E.g. in an equation with x & y as the unknowns you would need two different equations containing x and/or y to solve them
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Even if you keep the decimal, later on you will still have to remove it. It is just an easier way to solve the equation.
Tell me the equations first.