your equation is this...
x3 + 5x2 = 6x
get all the terms on the left side
x3 + 5x2 - 6x = 0
now factor out an "x"
x(x2 + 5x - 6) = 0
now factor the equation inside
x(x + 6)(x - 1)
from this you can find your x-values
x= 0, -6, and 1
now that you have your x-values your equation is solved. just use algebra to get all of the terms on the one side. then factor out anything that is common in all of the terms. then factor the polynomial. then find what values for "x" that satisfy the equation.
its 10
X= (3/5 , -2)
5x2 + 15x = 0 5x(x + 3) = 0 therefore, x = 0 or x + 3 = 0 that is, x = 0 or x = -3
Assuming that the 2 in "5x2" is a power (5x2), then no, this is not a linear equation. It is a parabolic equation.
5x2 = 3 then x2 = 3/5 so that x = sqrt(3/5) = ± 0.7746
3x4-7x3+5x2-3x+6
its 10
X= (3/5 , -2)
5x2 + 15x = 0 5x(x + 3) = 0 therefore, x = 0 or x + 3 = 0 that is, x = 0 or x = -3
Assuming that the 2 in "5x2" is a power (5x2), then no, this is not a linear equation. It is a parabolic equation.
5x2 = 3 then x2 = 3/5 so that x = sqrt(3/5) = ± 0.7746
6 + 10 = 16
1) 5x2-55=90 +55 +55 2) 10x=145 /10 /10 x=14.5
The discriminant is 385.
Yes
-5x2 = -75 x2 = 25 x = ±sqrt( 25 ) x = ±___
5x2=8x Divide with x on both sides5x= 8 Solve xx=8/5