1
log x + 2 = log 9 log x - log 9 = -2 log (x/9) = -2 x/9 = 10^(-2) x/9 = 1/10^2 x/9 = 1/100 x= 9/100 x=.09
x = 5, y = -1
That factors to (a + 1)(a + b) a = -1, -b b = -a
8+-1= 7 x=-1
1
3^(-2x + 2) = 81? log(3^(-2x + 2)) = log(81) (-2x+2)log(3) = log(81) -2x = log(81)/log(3) - 2 x = (-1/2)(log(81)/log(3)) + 1
-1 plus 1 = 0 plus 1 =1
log x + 2 = log 9 log x - log 9 = -2 log (x/9) = -2 x/9 = 10^(-2) x/9 = 1/10^2 x/9 = 1/100 x= 9/100 x=.09
11
a+a=1 2a=1 a=1/2
i have no clue what the answer is
log1 + log2 + log3 = log(1*2*3) = log6
x = 5, y = -1
That factors to (a + 1)(a + b) a = -1, -b b = -a
logx +7=1+log(x-1) 6=log(x-1)-logx 6=log[(x-1)/x] 10^6=(x-1)/x 1,000,000x=x-1 999,999x=-1 x=-1/999,999
log(x) + log(2) = log(2)Subtract log(2) from each side:log(x) = 0x = 100 = 1