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How do you solve n in factorial (3xn plus 9) divided by factorial (2xn plus 4)144?
Wiki User
∙ 6y ago
You cannot, because there is no solution.
5 is not a factor of 144. Therefore 5 is not a factor of (3n + 9)! / (2n + 4)!
Therefore (3n + 9) - (2n + 4) < 5
n < 0.
Also, 2n + 4 must be non-negative.
ie 2n >= -4 or n >= -2.
So the only possible values for n are -1 and -2.
But n = -1 gives 6!/2! = 720/2 = 360
while n = -2 gives 3!/0! = 6
Wiki User
∙ 5y ago
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4 factorial plus 4 factorial plus the square root of 4 divided by .4
How do you make 14 using four four's?
(33 ÷ 3) + 3 = 14
What is the value of abc if abc equals a factorial plus b factorial plus c factorial?
145 1! = 1 4! = 24 5! = 120
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(4 factorial plus the square root of 4) divided by point 4 minus 4 factorial
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(33 ÷ 3) + 3 = 14
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145 1! = 1 4! = 24 5! = 120
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y = 2
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What is the value of 6 factorial plus 4 factorial?
6! + 4! = 720 + 24 = 744
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25
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104
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y=5
