If your equation is in the form ax2 + bx + c, it can always be solved for x by using the quadratic formula.
x = -b plus or minus the square root of (b2 - 4ac) with the whole thing divided by 2a
Let's try an easy example: x2 + 3x - 4 = 0
That's factorable: (x + 4)(x - 1) so we already know what the answers are (-4, 1)
Now let's plug in the quadratic formula where a = 1, b = 3, c = -4
x = -3 plus or minus the square root of (3)2 -(4)1(-4) divided by 2(1)
Simplified, that's -3 plus or minus the square root of 25 divided by 2
Our two answers are (-3 + 5) divided by 2 and (-3 - 5) divided by 2
2/2 = 1 and -8/2 = -4
Non-factorable equations work just as well, except the answer won't be a whole number. It'll be some nasty decimal or an imaginary number.
Tell me the equations first.
You need as many equations as you have variables.
You can solve the system of equations with three variables using the substitute method, or using matrix operations.
If you don't learn to solve equations then guess and check is the only way to arrive at new information.
You would solve them in exactly the same way as you would solve linear equations with real coefficients. Whether you use substitution or elimination for pairs of equations, or matrix algebra for systems of equations depends on your requirements. But the methods remain the same.
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Tell me the equations first.
There are people who use this web site that can and will solve equations.
You can use a graph to solve systems of equations by plotting the two equations to see where they intersect
The answer depends on the nature of the equations.
You solve equations with fractions the same way you solve other equations. You perform various arithmetic operations on both sides of the equals sign until you get the result you want.
You need as many equations as you have variables.
One can solve equations of motion by graph by taking readings of the point of interception.
Its harder to solve the equations with grande numbers
Equations can be tricky, and solving two step equations is an important step beyond solving equations in one step. Solving two-step equations will help introduce students to solving equations in multiple steps, a skill necessary in Algebra I and II. To solve these types of equations, we use additive and multiplicative inverses to isolate and solve for the variable. Solving Two Step Equations Involving Fractions This video explains how to solve two step equations involving fractions.
The answer depends on whether they are linear, non-linear, differential or other types of equations.
To solve a system of equations, you need equations (number phrases with equal signs).