a squared plus b squared equals c squared so 3x3 + 3x3 is 54 and the square root of 54 is is the answer
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Remember the most powerful thing you know about right triangles:
(one leg)2 plus (the other leg)2 = (hypotenuse)2
You're given the lengths of both sides. Just put them in that formula, and do what
you have to do in order to get the length of the hypotenuse.
This isn't even a right triangle problem! This is an exercise to help you see
whether you know how to handle square roots. If you can't do this one, then
you need to make an appointment with the teacher, or with someone you know
who understands this stuff, and spend some time reviewing how to do the
arithmetic operations with square roots.
We're not going to show you how to do it, because doing it is the whole reason
for getting involved in this exercise. The reason you're doing it is not to get the
answer. Nobody needs the answer, and anybody who does knows how to find it.
The hypotenuse is 6. (The answer at the top is wrong.) You can use that to check
yourself when you try to do it, and see whether you've done it correctly.
Two isosceles right triangles, if joined hypotenuse-to-hypotenuse will make a square. Two squares, sided by side, make a rectangle which is a parallelogram, and not a square.
No because all right triangles have 2 legs and a hypotenuse. The hypotenuse is always longer than either leg so right triangles can't be equilateral triangles.
A diagonal bisecting a square creates two identical right triangles. The diagonal is the hypotenuse of a right triangles, so its length is the square root of the sums of the squares on the opposite two sides.
I quote " The square on the hypotenuse of a rightangled triangle..."
For right angled triangles it is the square root of square of side A added to square of side B (sorry i don't have a square sign on my keyboard) hypotenuse=square root of AxA+BxB
Two isosceles right triangles, if joined hypotenuse-to-hypotenuse will make a square. Two squares, sided by side, make a rectangle which is a parallelogram, and not a square.
they have at least one right angle. A square is the union of two isosceles right triangles. The hypotenuse of each triangle is the diagonal of the square.
No because all right triangles have 2 legs and a hypotenuse. The hypotenuse is always longer than either leg so right triangles can't be equilateral triangles.
A diagonal bisecting a square creates two identical right triangles. The diagonal is the hypotenuse of a right triangles, so its length is the square root of the sums of the squares on the opposite two sides.
If two right triangles have (hypotenuse and a leg of one) = (hypotenuse and the corresponding leg of the other) then the triangles are congruent.
I quote " The square on the hypotenuse of a rightangled triangle..."
The area is 71.29 square units
For right angled triangles it is the square root of square of side A added to square of side B (sorry i don't have a square sign on my keyboard) hypotenuse=square root of AxA+BxB
Yes. Consider the situation when: the right-angled triangles are also isosceles and the hypotenuse (longest side) of the triangles is equal to the side of the square. If you surround a square with four of right-angled triangles (the sides of the square being in contact with the hypotenuses of the triangles), you get a larger shape which is also a square. Taking this as a basic unit, you can make a tesselations. You can also make tessalations if you have two sets of squares, one with sides the same length of the hypotenuse of the triangles and one with sides the same length as the smaller sides of the triangles.
If two right triangles have the hypotenuse and leg of one equal respectively to the hypotenuse and leg of the other, then the triangles are congruent.
yes
If the hypotenuse and a leg of a right triangle are congruent to the hypotenuse and a leg of another right triangle, then the triangles are congruent.