use the SohCahToa method
sohcahtoa SOH|CAH|TOA S= O opposite over hypotenuse _ H C=A adjacent over hypotenuse _ H T=O opposite over adjacent _ A
Some Old Hags Can't Always Hide Their Old Age
Sin= Opposite/Hypotenuse Cos= Adjacent/Hypotenuse Tan= Opposite/Adjacent
The longest length would be the hypotenuse. You can use SOHCAHTOA to find the length.
use the SohCahToa method
sohcahtoa SOH|CAH|TOA S= O opposite over hypotenuse _ H C=A adjacent over hypotenuse _ H T=O opposite over adjacent _ A
Tyrone is socahtoa joe, i saw him vent in kfc
Use SOHCAHTOA, then cross multiply and divide.
Some Old Hags Can't Always Hide Their Old Age
Sin= Opposite/Hypotenuse Cos= Adjacent/Hypotenuse Tan= Opposite/Adjacent
D= vyt+1/2at2 a = (v2-v1)/t These are the two most basic formula that are used to figure out projectile motion questions, combine with SOHCAHTOA (trig) to solve simple projectile motion problems. Remember the horizontal velocity is always constant.
The longest length would be the hypotenuse. You can use SOHCAHTOA to find the length.
Sohcahtoa is an abbreviation (SOH) sine opposite hypotenuse (CAH) cosine adjacent hypotenuse (TOA) tangent opposite adjacent.
It is a trigonometric equation for a right triangle, to find a non-right-angle angle. Using SOHCAHTOA, it is the opposite side divided by the adjacent angle
If you have the length of two of the sides and one other angle you can use the law of sines.
SOHCAHTOA:SOH: Sin= Opposite over HypotenuseCAH: Cos=Adjacent over HypotenuseTOA: Tan=Opposite over Adjacenthttp://rml3.com/a20p/images/trig_sin_cos_tan.gif