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It means for any right angle triangle:-

sine = opposte/hypotenuse

cosine = adjacent/hypotenuse

tangent = opposite/adjacent

Q: How do you solve sohcahtoa?

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use the SohCahToa method

sohcahtoa SOH|CAH|TOA S= O opposite over hypotenuse _ H C=A adjacent over hypotenuse _ H T=O opposite over adjacent _ A

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Sin= Opposite/Hypotenuse Cos= Adjacent/Hypotenuse Tan= Opposite/Adjacent

The longest length would be the hypotenuse. You can use SOHCAHTOA to find the length.

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use the SohCahToa method

sohcahtoa SOH|CAH|TOA S= O opposite over hypotenuse _ H C=A adjacent over hypotenuse _ H T=O opposite over adjacent _ A

Tyrone is socahtoa joe, i saw him vent in kfc

Use SOHCAHTOA, then cross multiply and divide.

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D= vyt+1/2at2 a = (v2-v1)/t These are the two most basic formula that are used to figure out projectile motion questions, combine with SOHCAHTOA (trig) to solve simple projectile motion problems. Remember the horizontal velocity is always constant.

Sin= Opposite/Hypotenuse Cos= Adjacent/Hypotenuse Tan= Opposite/Adjacent

The longest length would be the hypotenuse. You can use SOHCAHTOA to find the length.

Sohcahtoa is an abbreviation (SOH) sine opposite hypotenuse (CAH) cosine adjacent hypotenuse (TOA) tangent opposite adjacent.

It is a trigonometric equation for a right triangle, to find a non-right-angle angle. Using SOHCAHTOA, it is the opposite side divided by the adjacent angle

If you have the length of two of the sides and one other angle you can use the law of sines.

SOHCAHTOA:SOH: Sin= Opposite over HypotenuseCAH: Cos=Adjacent over HypotenuseTOA: Tan=Opposite over Adjacenthttp://rml3.com/a20p/images/trig_sin_cos_tan.gif