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Assuming that the question is find x in x5=1610; the answer is 4.378901

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Q: How do you solve the proportion x5 equals 1610?
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How do you solve x5 equals 64x2?

x5 = x3 times x2. In this case x3 = 64 so x = cube root of 64 ie 4


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x10 = x5.x5 = (x5)2 [x power five whole squared] Equation is x10 + x5 - 2 Replacing x10 (x5)2+x5 - 2 Substituting x5 by Y Equation becomes Y2 + Y - 2 = 0 Y2 + 2Y - Y - 2 = 0 Y(Y + 2) - 1(Y+2) = 0 (Y-1)(Y+2) = 0 The values of Y are 1 and -2 Y = x5 = 1 Therefore, x = 1 Y = x5 = -2 x = fifth root of -2, which is an imaginary value.


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What is the missing prime factor of 75 equals 3 x5?

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