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Q: How do you solve the proportion x5 equals 1610?

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x5 = x3 times x2. In this case x3 = 64 so x = cube root of 64 ie 4

11x5=55 !

1,565 = x5 1,5651/5 = (x5)1/5 1,5651/5 = x5/5 1,5651/5 = x 4.3541 = x

5x-9Substitute 4 in for x5(4)-9=Solve.9-9=0the answer is zero.The answer is not zero you added when you were supposed to multiply so the real answer is 11.

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Related questions

x5 = x3 times x2. In this case x3 = 64 so x = cube root of 64 ie 4

a(x5) + b(x5) + c(x5) + d(x5) + e(x5) = abcde(a+b+c+d+e) x5 = abcdeThis equation has at least 5 variables. To solve for all of them requires at least 4 more equations.

x5 is an expression, not an equation nor an inequality. An expression cannot be solved.

11x5=55 !

1,565 = x5 1,5651/5 = (x5)1/5 1,5651/5 = x5/5 1,5651/5 = x 4.3541 = x

512 x 5 = 2,560

x10 = x5.x5 = (x5)2 [x power five whole squared] Equation is x10 + x5 - 2 Replacing x10 (x5)2+x5 - 2 Substituting x5 by Y Equation becomes Y2 + Y - 2 = 0 Y2 + 2Y - Y - 2 = 0 Y(Y + 2) - 1(Y+2) = 0 (Y-1)(Y+2) = 0 The values of Y are 1 and -2 Y = x5 = 1 Therefore, x = 1 Y = x5 = -2 x = fifth root of -2, which is an imaginary value.

5x-9Substitute 4 in for x5(4)-9=Solve.9-9=0the answer is zero.The answer is not zero you added when you were supposed to multiply so the real answer is 11.

-1

x10 =========================== Another contributor says: If the question means [ x5 + x5 ] then the sum is [ 2 x5 ].

5+5x5=30 but (5+5)x5=50

75 = 3 x 5 x 5

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