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∙ 8y agox - father's age
y - son's age
=> 9y+5=4y+20 => 5y=15 => y=3
x=9y => x=27
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∙ 8y agoThe son is 11, the father is 26
If x is the age of the son, then 5x would be the age of the father. In 6 years, the son would be x + 6 years old, where the father would be 3(x + 6) years old. Since the original age of the father is 5x, then in 6 years the father could also be said to be 5x + 6 years old. Setting these two expressions for the father's age as an equation, we then can solve for x, the son's age. 3(x + 6) = 5x +6 3x + 18 = 5x + 6 2x = 12 x = 6 The original age of the son is 6 and of the father (5x) is 30 years old. In 6 years, the son would be 12 and the father would be [3x + 18 or 5x + 6] 36 years old.
8
28
let x be the age of father and y be the age of the son....... now according to the question just make the equations and solve it with any method u prefer to be the most easiest to solve.........
The son is 11, the father is 26
If x is the age of the son, then 5x would be the age of the father. In 6 years, the son would be x + 6 years old, where the father would be 3(x + 6) years old. Since the original age of the father is 5x, then in 6 years the father could also be said to be 5x + 6 years old. Setting these two expressions for the father's age as an equation, we then can solve for x, the son's age. 3(x + 6) = 5x +6 3x + 18 = 5x + 6 2x = 12 x = 6 The original age of the son is 6 and of the father (5x) is 30 years old. In 6 years, the son would be 12 and the father would be [3x + 18 or 5x + 6] 36 years old.
28
8
let x be the age of father and y be the age of the son....... now according to the question just make the equations and solve it with any method u prefer to be the most easiest to solve.........
5*8=40 The father is 40years old
Age of the father is 20. Pretty young to be a father. Son is 8 years old. The equations are as folllows: x-2 = 3 (y-2) 2x = 5y Cheers
That only works for people who are eleven.
His son would be 9 years old (father would be 44)
a father is 30 times older than hi son.however after 18 years he will only be thrice as old as his sons age . find the present age of father
son is 10, father is 33
You can solve this by taking the two statements and expressing them as equations, then using elimination to solve a single variable: Let d = the dad's age and s = the son's age. We're told: d = 3s d + 11 = 2(s + 11) So we can substitute the first equation into the second one: 3s + 11 = 2(s + 11) 3s + 11 = 2s + 22 s = 11 So the son is 11 years old. We know that the father is three times that age, so he would be 33.