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∙ 2013-10-22 01:24:36The square root of 149 (7 squared plus 10 squared equals 149).
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you use Pythagoras theorem. Square of the Hypotenuse = square of the other 2 sides i.e ac squared = ab squared + bc square = 22 Squared + 32 Squared = 484 + 1024 = 1508 so ac = square root of 1508 = 38.83 cm(2 d.p)
ac + cb = ab = 9 2x - 1 + 3x = 9 5x -1 = 9 So 5x = 10 Thereby x =2. Also ac = 3 and cb = 6
56 cm squared
(b-c)(a+b)-ac
6(b - ac + b2 - bc)
6(ab - ac + b2 - bc)
carry the six then use the quadratic formula negative b plus or minus the squrare root of b squared minus 4 ac all over 2
carry the six then use the quadratic formula negative b plus or minus the squrare root of b squared minus 4 ac all over 2
it means like ac angle or a squared like in the phythangren theorem its a squared + b squared = c squared
negative b plus or minus the square root of b minus 4 times ac all over 2 a
The most surefire way to find the zeroes of a quadratic are to apply the quadratic formula. The formula says that the zeroes of quadratic equations which are generally written as ax2+bx+c=y can be found by taking (-b+/-(b2-4ac).5)/2a or if this notation makes no sense... negative b plus or minus the square-root of b squared minus four ac all over two a. Note: if b squared minus four ac is less than zero, the function has non-real roots
this is what you would: 4x+6=3x-1 -6 -6 ---- 4x=3x-7 -3x -3x ---- 1x=-7 ---- x=-7
Well. Multiply both sides by 'c'. After that you should have something like ac=b-4 then you add 4, to get this result 4+ac=b.
The square root of 149 (7 squared plus 10 squared equals 149).
y=mx+b A=xy; A=(pi)r^2; V=xyh; (-b= or - (b^2-4ac)^1/2)/2a ( actually read as negative b plus or minus the square root of b squared minus four ac, all divided by 2a....quadratic formula) This should get you, if you need more or this is not what you were looking for, let me know.