An equation is a true statement. [ 75 + 4 = -2 ] is a false statement.
Written algebraically, the equation is (2/A)=4.The first step is to move the variable A from the denominator. To do this, multiply both sides of the equation by A:A*(2/A)=4*AThe A in the denominator on the left is canceled out and we are left with:2=4*ATo solve for A divide both sides of the equation by 4:2/4=ATwo over four simplifies to one half, which equals A:1/2=A
The equation 4y = 2x + 2 cannot just be solved. If you are trying to solve a system, you need as many equations as you have variables (x and y in this case). Since you have two variables, you need two equations.For example, if you had:4y = 2x + 2 AND 2y = 4x + 4, then it would be possible to solve like so....first solve for one of the variables in one of the equations. Let's go for y in the second equation.2y = 4x + 4 ----> 2y/2 = 4x/2 + 4/2 ----> y = 2x + 2.now use this value of y and place it into the first equation and then you can solve for x.4(2x + 2) = 2x + 2 ----> 8x + 8 = 2x + 2 ----> 6x = -6 ----> x = -1now you can replace the -1 into either equation and solve for y4y = 2(-1) + 2 ----> 4y = -2 + 2 ----> 4y = 0 ----> y = 0So, if there is another equation for you to solve with, you can easily use this method to solve for both variables.
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It is not possible to solve the equation 2k3-4t k 2 t 4 because it is not clear.
An equation is a true statement. [ 75 + 4 = -2 ] is a false statement.
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Written algebraically, the equation is (2/A)=4.The first step is to move the variable A from the denominator. To do this, multiply both sides of the equation by A:A*(2/A)=4*AThe A in the denominator on the left is canceled out and we are left with:2=4*ATo solve for A divide both sides of the equation by 4:2/4=ATwo over four simplifies to one half, which equals A:1/2=A
If you update the answer with the actual equation i can talk you through it. 4 + 2 =X (2 - 5 = 2
A two-step equation is an equation that requires two steps to solve We must eliminate any constant that is on the same side as the variable first To solve, use the inverse operations to isolate the variable by itself Remember whatever you do to one side, you must do to the other
Mathematical substitution is the process of using one equation to solve for multiple variables. For example: Equation 1: x + y = 4 Equation 2: 2x + y = 16 Using equation 1, solve for y: y = 4 - x <-- Plug this into equation 2. This is substitution because you are replacing y in equation 2 with what y is equal to in equation 1. 2x + y = 16 ----> 2x + (4 - x) = 16 Now you can solve for x: x + 4 = 16; x = 12 You can then substitute the value of x back into the equation that is solved for y: y = 4 - 12; y = -8 Check both equations: Equation 1: -8 + 12 = 4; 4 = 4 (Correct) Equation 2: 2(12) + (-8) = 16; 24 - 8 = 16; 16 = 16 (Correct) We have successfully used substitution to solve for two different variables, x and y.
3(2x-4)=2(4x+3)
The equation 4y = 2x + 2 cannot just be solved. If you are trying to solve a system, you need as many equations as you have variables (x and y in this case). Since you have two variables, you need two equations.For example, if you had:4y = 2x + 2 AND 2y = 4x + 4, then it would be possible to solve like so....first solve for one of the variables in one of the equations. Let's go for y in the second equation.2y = 4x + 4 ----> 2y/2 = 4x/2 + 4/2 ----> y = 2x + 2.now use this value of y and place it into the first equation and then you can solve for x.4(2x + 2) = 2x + 2 ----> 8x + 8 = 2x + 2 ----> 6x = -6 ----> x = -1now you can replace the -1 into either equation and solve for y4y = 2(-1) + 2 ----> 4y = -2 + 2 ----> 4y = 0 ----> y = 0So, if there is another equation for you to solve with, you can easily use this method to solve for both variables.
You would do it it by oppisites. 3+2+4=9 which equals C.
There appears to be no equation in the question: only some disjoint expressions. Expressions cannot be solved.
Easy! if -a = -4 then a = 4!!
depends on the question but an EXPONENTIAL EQUATION is in the for 2^x = 4 and you have to solve for x.